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quester [9]
3 years ago
5

Use the linear combination method to solve the system of equations. Explain each step of your solution.

Mathematics
1 answer:
Vika [28.1K]3 years ago
7 0

Answer:

1)y=-3+5x

2)y=5/2-1/2x

Step-by-step explanation:

for both equations

1) get your y by it self (subtract -5x and your new equation is now -y=-5x+3)

2)(reminder y can't be negative if it is negative) then you divide by -1 of both sides

3) your equation should now be y=5x-3

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Subtract --4x2 + 3x - 7 from 8x2 + 2x - 3
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Answer:

23

Steps ig

((8x2) +2x(-3)))-(((-(-4)) x 2) +( 3 x( -7)) =23

5 0
3 years ago
Need help asap
Marizza181 [45]
Its b for sure i worked it out
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4 years ago
N0 If n=143 what is the answer a b or c
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Answer:

C

Step-by-step explanation:

Well, anything multiplied by zero is zero.

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Read 2 more answers
The point R(-3,a,-1) is the midpoint of the line segment jointing the points P(1,2,b)
wlad13 [49]

Answer:

The values are:

  • a = -5/2
  • b = -6
  • c = -7

Step-by-step explanation:

Given:

  • P = (x₁, y₁, z₁) = (1, 2, b)  
  • Q =  (x₂, y₂, z₂) = (c, -7, 4)  
  • m = R = (x, y, z) = (-3, a, -1)

To Determine:

a = ?

b = ?

c = ?

Determining the values of a, b, and c

Using the mid-point formula

m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)

  • As the point R(-3, a, -1) is the midpoint of the line segment jointing the points P(1,2,b)  and Q(c,-7,4), so
  • m = R = (x, y, z) = (-3, a, -1)

Using the mid-point formula

m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)

given

(x₁, y₁, z₁) = (1, 2, b) = P

(x₂, y₂, z₂) = (c, -7, 4) = Q

m = (x, y, z) = (-3, a, -1) = R

substituting the value of (x₁, y₁, z₁) = (1, 2, b) = P,   (x₂, y₂, z₂) = (c, -7, 4) = Q, and m = (x, y, z) = (-3, a, -1) = R in the mid-point formula

m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)

\left(x,\:y,\:z\right)\:=\:\left(\frac{1+c}{2},\:\frac{2+\left(-7\right)}{2},\:\frac{b+4}{2}\right)

as (x, y, z) = (-3, a, -1), so

\left(-3,\:a,\:-1\right)\:=\:\left(\frac{1+c}{2},\:\frac{2+\left(-7\right)}{2},\:\frac{b+4}{2}\right)

<u>Determining 'c'</u>

-3 = (1+c) / (2)

-3 × 2 = 1+c

1+c = -6

c = -6 - 1

c = -7

<u>Determining 'a'</u>

a = (2+(-7)) / 2

2a = 2-7

2a = -5

a = -5/2

<u>Determining 'b'</u>

-1 = (b+4) / 2

-2 = b+4

b = -2-4

b = -6

Therefore, the values are:

  • a = -5/2
  • b = -6
  • c = -7
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Nikitich [7]
I’m pretty sure it’s irrational
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