The absolute difference between the greatest and the least of these three numbers in the arithmetic sequence is 10.
The sequence is an arithmetic sequence. Therefore,
d = common difference
let
a = centre term
Therefore, the 3 consecutive term will be as follows
a - d, a, a + d
a - d + a + a + d = 27
3a = 27
a = 27 / 3
a = 9
Therefore,
(a-d)² + (a)² + (a + d)² = 293
(a²-2ad+d²) + 9² + (a² + 2ad + d²) = 293
(81 - 18d + d²) + 81 + (81 + 18d + d²) = 293
243 + 2d² = 293
2d² = 50
d² = 50 / 2
d = √25
d = 5
common difference = 5
Therefore, the 3 numbers are as follows
9 - 5 , 9, 9 + 5 = 4, 9, 14
The difference between the greatest and the least of these 3 numbers are as follows:
14 - 4 = 10
learn more on Arithmetic progression: brainly.com/question/25749583?referrer=searchResults
They are both simple exercises in addition.
The solutions are:
(-65) x (-2) = <em>130</em>
(5j) + (10j) =<em> 15j</em>
Answer:
(x,y)=(-13,-12)
Step-by-step explanation:
5x - 7y = 19
7x - 7y = -7 Multiply both sides of the equation by -1
Which then gives you :
5x-7y=19 Sum the equations vertically to eliminate
-7x+7y=7 at least on variable
-2x=26 Divide both sides of the equation by -2
X=-13 Substitute the given value of x into the equation 7x - 7y =-7
7 x(-13)-7y=-7 solve the equation for y
y=-12
Thus gives you (-13,-12)
Hope this was useful!!! Sorry if it's wrong.
Answer:
40--C A ---is not[figure it out in your own words,your teacher might suspect something] and B---times 40
Step-by-step explanation:
b--40+40=80 80+40=120 and 120+40=160 A=subtract 40 from all the other answers such as 40-160=120 40-120=80 and 40-80=40
Answer:
B. 1,500’
Step-by-step explanation:
Given;
dimension of the rectangular house, = 35’ x 40’
The actual total linear footage of lumber needed = 35’ x 40’ = 1,400'
The rough estimate should be greater than the actual estimate in 100s;
rough estimate = 1,400' + 100' = 1,500'
Therefore, the rough estimate of the total linear footage of lumber needed is 1,500'.
