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Leokris [45]
3 years ago
15

What is -65 x -2? 5j + 10j?

Mathematics
1 answer:
dolphi86 [110]3 years ago
8 0

They are both simple exercises in addition.
The solutions are:

         (-65) x (-2)  =  <em>130</em>

           (5j) + (10j)  =<em>  15j</em>


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2n + 4n = 42<br><br> Answer: the value of n is .....
Gennadij [26K]

Answer:

7

Step-by-step explanation:

2n + 4n = 6n, adding like terms

6n = 42

6n/6 = 42/6

n = 7

5 0
3 years ago
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Wittaler [7]
The Correct Answer is : 4x - 4 * 2

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3 years ago
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What are the zeros of f(x) = x(x-7)?
den301095 [7]

Answer:

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Step-by-step explanation:

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3 years ago
The sides of a triangle are x,x+1,2x-1 and its area is x root 10. Find the value of x
Marianna [84]
<span>You can use Heron's formula to solve this problem.

</span>A= \sqrt{s(s-a)(s-b)(s-c)} , where A is the area; a,b,с are the sides;  s<span> is the </span>semiperimeter<span> of the triangle
</span>s= \frac{a+b+c}{2}

<span>According to conditions:
</span>a = x
b = x+1
с = 2x-1

<span>Calculate the semiperimeter:
</span>s= \frac{x+x+1+2x-1}{2} = \frac{4x}{2}=2x

<span>Now we can compose and solve the equation according to Heron's formula:
</span>\sqrt{2x(2x-x)(2x-(x+1))(2x-(2x-1))}=x \sqrt{10}   \\  \sqrt{2x(x)(2x-x-1)(2x-2x+1)}=x \sqrt{10} \\  \sqrt{2x^2(x-1)(1)}=x \sqrt{10} \\  \sqrt{2x^3-2x^2}=x \sqrt{10}  \  \  \ |()^2 \\ 2x^3-2x^2=10x^2 \\ 2x^3-2x^2-10x^2=0 \\ 2x^3-12x^2=0 \ \ |:2 \\ x^3-6x^2=0 \\ x^2(x-6)=0 \\  \\ x^2=0 \\ x=0 \ \ \ \O \\ or \\ x-6=0 \\ x=6

<span>As a result, x = 6 is your answer.
 
I hope this helped.</span>
7 0
3 years ago
5 + 8n = 7(-7 + 4n) -6
Luba_88 [7]

Answer:

n = 3

Step-by-step explanation:

Given

5 + 8n = 7(- 7 + 4n) - 6 ← distribute parenthesis on right side

5 + 8n = - 49 + 28n - 6 ( subtract 28n from both sides )

5 - 20n = - 55 ( subtract 5 from both sides )

- 20n = - 60 ( divide both sides by - 20 )

n = \frac{-60}{-20} = 3

6 0
3 years ago
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