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azamat
3 years ago
9

What is the simplified form of the following expression?

Mathematics
2 answers:
Alex3 years ago
8 0

Hey there!

  • \bold{\frac{9+4^2}{5}}
  • \bold{4^2=4\times4=16}
  • \bold{\frac{9+16}{5}}
  • \bold{9+16=25}
  • \bold{\frac{25\div5=5}{5\div5=1}}
  • \bold{\frac{5}{1}=5}
  • \boxed{\boxed{\bold{Answer:A.5}}}\checkmark

\starGood luck on your assignment and enjoy your day\star

~\frak{LoveYourselfFirst:)}

tigry1 [53]3 years ago
7 0

Hello there!

Answer:

\boxed{A.=5}

Step-by-step explanation:

PEMDAS

Order of operations

Parenthesis

Exponent

Multiply

Divide

Add

Subtract

Left/Right

First, you do exponent.

4^2=4*4=16

\frac{9+16}{5}

Add by the numerator.

9+16=25

\frac{25}{5}=5

\boxed{5}, <em>is the CORRECT/FINAL ANSWER!</em>

<em>Hope this helps you!</em>

<em>Have a nice day! :)</em>

<em>:D</em>

<em>-Charlie</em>

<em>Thanks!</em>

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Using the formula for area of a circle:

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Replace area with the given value:

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Divide both sides by pi

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Solve for radius by taking the square root of both sides

Radius = sqrt(12.62)

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You want to solve 11% of what number is 22. Explain how you can solve that by using a proportion
Doss [256]
Write the first ratio as 11/100 and set it equal to 22/n.

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What this solving system of equations?<br> x+y=-3<br> y=x^2+4x+1
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8 0
3 years ago
The following prices, in dollars, of 7.5-cubic-foot refrigerators were recorded from a random sample. 314 305 344 283 285 310​ 3
Mariana [72]

Answer:

t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109      

The degrees of freedom are given by:

df=n-1=10-1=9  

And the p value would be given by:

p_v =P(t_{9}>1.109)=0.148  

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

Step-by-step explanation:

Information given

314 305 344 283 285 310​ 383​ 285​ 300​ 300

We can calculate the sample mean and deviation with the following formula:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}

\bar X=310.9 represent the sample mean      

s=31.09 represent the standard deviation for the sample      

n=10 sample size      

\mu_o =300 represent the value to test

\alpha=0.05 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to verify if the true mean is greater than 300, the system of hypothesis would be:      

Null hypothesis:\mu \leq 300      

Alternative hypothesis:\mu > 300      

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

Replacing the info given we got:

t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109      

The degrees of freedom are given by:

df=n-1=10-1=9  

And the p value would be given by:

p_v =P(t_{9}>1.109)=0.148  

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

6 0
3 years ago
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