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3 years ago

Please please please help me

Mathematics

2 answers:

Leviafan [203]3 years ago

8 0

The correct answer is 17 what i did was plug in 17 where ever you see x so x2 would be 17x2 an then plus the 5 gives u 39 3x 17x3=51 51+10=61 now add the totals 61 plus 39 gives u 100

Sergeeva-Olga [200]3 years ago

3 0

Answer:

D. 17

Step-by-step explanation:

1. Set up an equation (2x + 5) + (3x + 10) = 100

2. 2x + 3x= 5x and 5 + 10 = 15

3. The equation simplified 5x + 15 = 100

4. Move the 15 to the other side of the equation. 5x = 100 - 15

5. 5x = 85

6. Finally, divide 85/5

7. Our final answer is 17.

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An artist is painting a flower pot that each require 1/34 gallons of paint what is the maximum numbers of flowerpots the artist

lara [203]

Answer:

Step-by-step explanation:

Hello There!

We can easily calculate the amount of flower pots he can paint by dividing the amount of paint he has by how much paint each flower pot requires

$\frac{.75}{\frac{1}{34} } =25.5$

The closest number is 24 therefore your answer is C

8 0

3 years ago

If your input is 5 what is the output?

Debora [2.8K]

Answer:

When the input is 5, the output is 11.

Step-by-step explanation:

Replace x with 5: 3(5) - 4 = 15 - 4 = 11

When the input is 5, the output is 11.

8 0

2 years ago

Read 2 more answers

The martinez family has a walkway around their swimming pool. the area of the walkway can

DiKsa [7]

The width of the walkaway be 4 feet.

<h3>What is Discriminant Formula?</h3>

The discriminant formula is used to determine the nature of the roots of a quadratic equation. The discriminant of a quadratic equation $ax^{2} +bx+c=0$ is D = $b^{2} -4ac$

If D > 0, then the equation has two real distinct roots.

If D = 0, then the equation has only one real root.

Given that: $Area\; of \;walkway,\; a(w)\;= 4w^{2} + 100 w$

also, area of walkaway = 464 square feet.

So, $4w^{2} + 100 w =464$

$4w^{2} + 100 w -464=0$

Using Discriminant method,

a=4, b=100, c=-464

$w= \frac{-b\pm\sqrt{b^{2}-4ac} }{2a}$

w= $\frac{-100\pm\sqrt{(100)^{2}-4*4*(-464)} }{2*4}$

w= $\frac{-100\pm\sqrt{17424} }{8}$

So, $w_1= \frac{-100+\sqrt{17424} }{8} \;\;\;\; w_2= \frac{-100-\sqrt{17424} }{8}$

$w_1= \frac{-100+132 }{8} \;\;\;\; w_2= \frac{-100-132}{8}$

$w_1 = 4 \;\;\;\; and \;\;\; w_2= -29$

Hence the width of the walkaway be 4 feet.

Learn more about discriminant formula here:

brainly.com/question/2615966

#SPJ1

8 0

1 year ago

What is the measure of an exterior angle of a regular 7-sided polygon? The answer must be a decimal.

ale4655 [162]

1 interior angle = [(n-2)180]÷n
= [(7-2)×180]÷7
= 900÷7 = 128.57 °
an exterior angle = 180 - interior
= 180-128.57
= 51.43°

8 0

2 years ago

Use the formula for the cosine of the difference of two angles to find the exact value of the following expression.

Zolol [24]

Answer:

Exact value of Cos(45° - 60°) is 0.96 using difference of two angles.

Step-by-step explanation:

Given:

Cos(45° - 60°)

We have to apply the formula of cosine for difference of the two angles.

Formula:

$cos(a-b)=cos(a)\ cos(b)+sin(a)\ sin(b)$

Plugging the values.

⇒ $cos(45-60)=cos(45)\ cos(60) + sin(45)\ sin(60)$

We know that the values :

$sin(45) =cos(45) = \frac{1}{\sqrt{2} }$

$sin(60)=\frac{\sqrt{3} }{2}$ and $cos(60)=\frac{1}{2}$

So,

⇒ $cos(45-60)=(\frac{1}{\sqrt{2} } \times \frac{1}{2} ) + (\frac{1}{\sqrt{2} } \times \frac{\sqrt{3} }{2})$

⇒ $cos(45-60)=(\frac{1}{2\sqrt{2} } + \frac{\sqrt{3} }{2\sqrt{2} })$

⇒ $cos(45-60)=(\frac{1+\sqrt{3} }{2\sqrt{2} } )$

⇒ $cos(45-60)=(\frac{1+\sqrt{3} }{2\sqrt{2} } )\times \frac{2\sqrt{2} }{2\sqrt{2} }$ ...rationalizing

⇒ $cos(45-60)=\frac{2\sqrt{2} +2\sqrt{6} }{ 8}$

⇒ $cos(45-60)=\frac{2(\sqrt{2}+\sqrt{6})}{8}$ ...taking 2 as a common factor

⇒ $cos(45-60)=\frac{(\sqrt{2}+\sqrt{6})}{4}$

To find the exact values we have to put the values of sq-rt .

As, $\sqrt{2}=1.41$ and $\sqrt{6} =2.44$

Then

⇒ $cos(45-60)=\frac{( 1.41+2.44)}{4}$

⇒ $cos(45-60)=\frac{( 3.85)}{4}$

⇒ $cos(45-60)=0.96$

So the exact value of Cos(45° - 60°) is 0.96 using difference of two angles.

3 0

2 years ago