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DiKsa [7]
3 years ago
7

Polygon ABCD is defined by the points A(-4,2) B(-2, 4), C(1, 3) & D(2,2). Match the coordinates of the points of the transfo

rmed polygons to their correct values

Mathematics
1 answer:
dalvyx [7]3 years ago
8 0

Answer:

D'(-2, 2); C''(3, -1); A'''(4, -2); and B''(4, 2)

Step-by-step explanation:

See attachment for the figure.

<u>For D'</u>, rotating the point (2, 2) 90° counterclockwise. This maps each point (x, y)→(-y, x); it takes (2, 2)→(-2, 2).  

For C'', rotating the point (1, 3) 90° clockwise.  This maps each point (x, y)→(y, -x); it takes (1, 3)→(3, -1).

For A''', rotating the point (-4, 2) 180° clockwise.  This maps every point (x, y)→(-x, -y); it takes (-4, 2)→(4, -2).

For B'', rotating the point (-2, 4) 270° counterclockwise.  This is the similar as rotating the point 90° clockwise.  This maps every point (x, y)→(y, -x); it takes (-2, 4)→(4, 2).

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X^2+4x+y^2-10y+20=30 find the center of the circle by completing the square
swat32

Answer:

a). Center of the circle = (-2, 5)

b). Equation of the line ⇒ y = -\frac{4}{5}x+\frac{58}{5}

Step-by-step explanation:

Equation of the circle is,

x² + 4x + y²- 10y + 20 = 30

a). [x² + 2(2)x + 4 - 4] + [y²- 2(5)y + 25] - 25 + 20 = 30

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By comparing this equation with the standard equation of a circle,

    Center of the circle is (-2, 5).

b). A point (2, 10) lies on this circle.

    Slope of the line joining this point to the center (-2, 5),

    m_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

          = \frac{10-5}{2+2}

          = \frac{5}{4}

    Let the slope of the tangent which is perpendicular to this line is 'm_{2}'

    Then by the property of perpendicular lines,

          m_{1}\times m_{2}=-1

          \frac{5}{4}\times m_{2}=-1

                 m_{2}=-\frac{4}{5}

   Now the equation of the line passing though (2, 10) having slope m_{2}=-\frac{4}{5}

           y - y' = m_{2}(x-x')

           y - 10 = -\frac{4}{5}(x-2)

           y - 10 = -\frac{4}{5}x+\frac{8}{5}

                  y = -\frac{4}{5}x+\frac{8}{5}+10

                  y = -\frac{4}{5}x+\frac{58}{5}

Therefore, equation of the line will be, y = -\frac{4}{5}x+\frac{58}{5}

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