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bonufazy [111]
3 years ago
9

Together Elizabeth and Norman have 45 postcards. Norman has 4 Times as many postcards as Elizabeth. How many postcards are in No

rman's collection? how many postcards are in Elizabeth's collection?
Mathematics
1 answer:
stiv31 [10]3 years ago
6 0

Answer:

boy 36

girl 9

............

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What is the solution to the equation 3/5n - 4/5 = 1/5n?
antiseptic1488 [7]

Answer: 2

Step-by-step explanation:

3 0
3 years ago
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Bobby and his family went to the playground. The slide is 13
Nonamiya [84]

Answer:

it would be close to 12 ft im not 100% sure though the measurements are a little off

Step-by-step explanation:

hypotenuse is 13

then you have the adjacent = 7

13^2 = 169

7^2= 49

169-49=120

the square root of 121 is 11 wich is fairly close to 120(doesnt have one because its not exact)

there is two extra feet so 11 +2 is 13 but there  was a little less then 11 so i had sid roughly around 12

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4 0
4 years ago
Describe how you could represent the fraction 4/10 using a model or number line. Dont make the answer huge thank you
Rzqust [24]

Answer:

As a model for representing fractions, the number line differs from other models (e.g., sets, regions) in several important ways. First, a length represents the unit, and the number line model suggests not only iteration of the unit but also simultaneous subdivisions of all iterated units. That is, the number line can be treated as a ruler.

Step-by-step explanation:

3 0
3 years ago
If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b
Andrews [41]

Answer:

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

56 = 1, 2, 4, 7, 8, 14, 28, 56

As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

fourth possible pairs = (3/8)*(5/7) = 15/56

So, we can get those four possible pairs. Among those, first 3 pairs are different. Therefore, those are possible pairs.

4 0
3 years ago
CAN SOMEONE HELP ME​
ANTONII [103]

Answer:

C is the answer

you can also see

7 0
3 years ago
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