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Vesnalui [34]
3 years ago
10

An art teacher has 18 pictures to hang on the wall.

Mathematics
2 answers:
uranmaximum [27]3 years ago
8 0
The answer is B.
6 x 3 = 18
Please mark as brainliest.
Naily [24]3 years ago
8 0
The answer is B because the other guy said so so you better listen
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Write the following number as ratios of integers
s2008m [1.1K]

Our goal here is to somehow "surgically remove" the repeating part of the number, so let's start by putting the original value in a variable and messing around with it a bit.

We'll let x=7.\overline{6}. We want to cut the 0.\overline{6} bit off completely, so let's create the scalpel that'll let us do that. If x=7.\overline{6}, then we can also say that 10x=76.\overline{6}. Maybe I was lying a bit: the x is our real scalpel here, and 10x is where we'll be making the cut. Mathematically, a "cut" is almost always shorthand for subtraction, so let's see what our operation (cutting x off of 10x) leaves us with:

10x-x=76.\overline{6}-7.\overline{6}\\9x=69

The operation was a success! We can now simply divide either side by 9 to find x = 69/9, which, when reduced by dividing the numerator and denominator by 3, gives us x=23/3

7 0
3 years ago
I’m not sure how to do this problem
strojnjashka [21]
The first one would be x^12
6 0
3 years ago
Abraham is taking his mother out to a restaurant for a mother's day dinner . He orders a meal that cost \$12 and his mom orders
White raven [17]

Answer:

$38.26

Step-by-step explanation:

add the amounts together and multiply by 0.075 and 0.15 add these answers to the original amount

6 0
3 years ago
Write and graph exponential functions to model the number of students at school A and at school B as a function of number of yea
Westkost [7]

Answer:

2^8 2x2x2x2x2x2x2x2=256

Step-by-step explanation:

8 0
3 years ago
Find the area under the standard normal probability distribution between the following pairs of​ z-scores. a. z=0 and z=3.00 e.
prohojiy [21]

Answer:

a. P(0 < z < 3.00) =  0.4987

b. P(0 < z < 1.00) =  0.3414

c. P(0 < z < 2.00) = 0.4773

d. P(0 < z < 0.79) = 0.2852

e. P(-3.00 < z < 0) = 0.4987

f. P(-1.00 < z < 0) = 0.3414

g. P(-1.58 < z < 0) = 0.4429

h. P(-0.79 < z < 0) = 0.2852

Step-by-step explanation:

Find the area under the standard normal probability distribution between the following pairs of​ z-scores.

a. z=0 and z=3.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 3.00) = 0.9987

Thus;

P(0 < z < 3.00) = 0.9987 - 0.5

P(0 < z < 3.00) =  0.4987

b. b. z=0 and z=1.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 1.00) = 0.8414

Thus;

P(0 < z < 1.00) = 0.8414 - 0.5

P(0 < z < 1.00) =  0.3414

c. z=0 and z=2.00

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 2.00) = 0.9773

Thus;

P(0 < z < 2.00) = 0.9773 - 0.5

P(0 < z < 2.00) = 0.4773

d.  z=0 and z=0.79

From the standard normal distribution tables,

P(Z< 0) = 0.5  and P (Z< 0.79) = 0.7852

Thus;

P(0 < z < 0.79) = 0.7852- 0.5

P(0 < z < 0.79) = 0.2852

e. z=−3.00 and z=0

From the standard normal distribution tables,

P(Z< -3.00) = 0.0014  and P(Z< 0) = 0.5

Thus;

P(-3.00 < z < 0 ) = 0.5 - 0.0013

P(-3.00 < z < 0) = 0.4987

f. z=−1.00 and z=0

From the standard normal distribution tables,

P(Z< -1.00) = 0.1587  and P(Z< 0) = 0.5

Thus;

P(-1.00 < z < 0 ) = 0.5 -  0.1586

P(-1.00 < z < 0) = 0.3414

g. z=−1.58 and z=0

From the standard normal distribution tables,

P(Z< -1.58) = 0.0571  and P(Z< 0) = 0.5

Thus;

P(-1.58 < z < 0 ) = 0.5 -  0.0571

P(-1.58 < z < 0) = 0.4429

h. z=−0.79 and z=0

From the standard normal distribution tables,

P(Z< -0.79) = 0.2148  and P(Z< 0) = 0.5

Thus;

P(-0.79 < z < 0 ) = 0.5 -  0.2148

P(-0.79 < z < 0) = 0.2852

8 0
3 years ago
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