<span>let 2x be the length of rectangw where x is value of x of point on parabola width is represented as y is the length.
Area = 2x*y = 2x (5-x^2) = 10x -2x^3
maximize Area by finding x value where derivative is zero
dA/dx = 10 -6x^2 = 0
--> x = sqrt(5/3)
optimal dimensions: length = 2sqrt(5/3) width = 10/3</span>
Answer:
480 different sandwiches
Step-by-step explanation:
To find how many sandwiches can be made, we need to find the number of possibilities for each choice: bread, protein, cheese, vegetables.
Bread: 3 types -> combination of 3 choose 1 -> 3
Protein: 4 types -> combination of 4 choose 1 -> 4
Cheese: 4 types -> combination of 4 choose 1 -> 4
Vegetables: 5 types -> combination of 5 choose 2 -> 5!/(3!*2!) = 5*4/2 = 10
So the number of different sandwiches is:
3 * 4 * 4 * 10 = 480
Answer: There is no solution
Step-by-step explanation:
$You would need something to plug in the x points
Answer:
x=3, -5.
Step-by-step explanation:
x^2+2x+25=40
x^2+2x+25-40=0
x^2+2x-15=0
factor out the trinomial,
(x-3)(x+5)=0
zero property,
x-3=0, x+5=0,
x=0+3=3,
x=0-5=-5.
She must by 60 tiles for the prices to be even. 24+0.79x=1.19x x=amount of tiles. you subtract 0.79x from both sides. you should get 24=0.4x. then you divide 0.4 from both sides. you should get 60=x
