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DIA [1.3K]
2 years ago
10

Help me with this please!?!?!?!?!

Mathematics
1 answer:
I am Lyosha [343]2 years ago
5 0

Answer:

17/4

Step-by-step explanation:

add the fractions

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R(6 1/2)=5(6 1/2) - 3.5
Airida [17]

The value of r in the equation r(61/2)=5(61/2)-3.5 is 4.88.

Given an equation r(61/2)=5(61/2)-3.5.

We are required to find the value of r in the equation.

Equation is like a relationship between two or more variable that are expressed in equal to form. The equation of two variables look like ax+by=c. It may be a linear equation, quadratic equation, cubic equation and many more depending on the powers of the variable present in that equation.

In our equation the variable is r.

The equation is given as:

r(61/2)=5(61/2)-3.5

r(61/2)=305/2-3.5

r(61/2)=(305-7)/2

r(61/2)=298/2

r=(298*2)/(2*61)

r=596/122

r=4.88

Hence the value of r in the equation r(61/2)=5(61/2)-3.5 is 4.88.

Learn more about equation at brainly.com/question/2972832

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3 0
1 year ago
Fernando has $10 to buy snacks for his friends at the baseball game. A
ryzh [129]

Answer:

p ≤ 6.48

Step-by-step explanation:

Apex

8 0
3 years ago
The bottom of a ladder must be placed 5 feet from a building. the ladder is 14 feet long. how far above the ground does the ladd
Kryger [21]
Check the picture below.

6 0
3 years ago
The prior probabilities for events A1 and A2 are P(A1) = 0.30 and P(A2) = 0.55. It is also known that P(A1 ∩ A2) = 0. Suppose P(
k0ka [10]

We're given the following probabilities:

P(A_1)=0.30

P(A_2)=0.55

P(A_1\cap A_2)=0

P(B\mid A_1)=0.20

P(B\mid A_2)=0.05

(a) Yes, A_1 and A_2 are mutually exclusive. This is exactly what zero probability of their intersection means. The two events cannot occur simultaneously.

(b) Use the definition of conditional probability to expand:

P(A_1\cap B)=P(A_1)P(B\mid A_1)=0.30\cdot0.20=0.06

P(A_2\cap B)=P(A_2)P(B\mid A_2)=0.55\cdot0.05=0.0275

(c) By the law of total probability,

P(B)=P(A_1\cap B)+P(A_2\cap B)=0.06+0.0275=0.0875

(d) Bayes' theorem says

P(A_1\mid B)=\dfrac{P(A_1)P(B\mid A_1)}{P(B)}=\dfrac{0.30\cdot0.20}{0.0875}\approx0.686

P(A_2\mid B)=\dfrac{P(A_2)P(B\mid A_2)}{P(B)}=\dfrac{0.55\cdot0.05}{0.0875}\approx0.314

3 0
3 years ago
The formula for the area of a trapeziod is A=1/2h(b1+b2), where b1 and b2 are both the bases and h is the height. Find the value
Mice21 [21]
Does it list what both of the bases are?
7 0
3 years ago
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