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3 years ago

7

The middle school baseball team, the badgers won 20 games last year. This year they won 22 games. What is the percent increase o

f games won from last year to this year ?

1 answer:

viktelen [127]3 years ago

4 0

Answer:

22/20×100%=110%

110%-100%=10%

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A polynomial has been factored, as shown below: f(x) = (x − 6)(x + 5)(x − 9) What are the zeros of the polynomial? (5 points)

soldi70 [24.7K]

<span>x=6</span>, <span>x=−5</span> or <span>x=9</span>

Explanation:

<span><span>f<span>(x)</span></span>=<span>(x−6)</span><span>(x+5)</span><span>(x−9)</span></span>

If all of the linear factors are non-zero, then so is their product <span>f<span>(x)</span></span>.

If any of the linear factors is zero, then so is their product <span>f<span>(x)</span></span>.

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3 years ago

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Leto [7]

Sorry, cannot just give you answers without your input.
I'd suggest that you look up online or in your textbook each of the items under "Type of Boundary." The results you'd get will likely help you fill in the rest of the boxes.

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3 years ago

An office is divided into 8 cubicles. How many of the cubicles are carpeted if only 1/4 of the cubicles are carpeted?

Bas_tet [7]

1/4 of 8 is 2. So 2 of the cubicles are carpeted.

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3 years ago

Read 2 more answers

Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!

LUCKY_DIMON [66]

Answer:

$=8\sqrt{15}b^{\frac{7}{2}}$

Step-by-step explanation:

$\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}$

$=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}$

$=\sqrt{40}b^2\sqrt{24b^3}$

$\sqrt{24b^3}$

$=\sqrt{24}\sqrt{b^3}$

$=\sqrt{24}b^{\frac{3}{2}}$

$=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$\sqrt{2^3}$

$=2^{3\cdot \frac{1}{2}$

$=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}$

$2^{\frac{3}{2}+\frac{3}{2}}$

$=2^3$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}$

$b^{\frac{3}{2}+2}$

$=b^{\frac{7}{2}}$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}$

$=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}$

$=8\sqrt{15}b^{\frac{7}{2}}$

4 0

3 years ago

3(x + 4) = 3x + 12 solve for x

iris [78.8K]

Answer:

all real numbers.

Step-by-step explanation:

First, distribute 3 to all terms within the parenthesis:

3(x + 4) = 3(x) + 3(4) = 3x + 12

3x + 12 = 3x + 12

Because both sides are the same, your answer for x is "all real numbers".

~

8 0

3 years ago