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Ratling [72]
3 years ago
7

The middle school baseball team, the badgers won 20 games last year. This year they won 22 games. What is the percent increase o

f games won from last year to this year ?
Mathematics
1 answer:
viktelen [127]3 years ago
4 0

Answer:

22/20×100%=110%

110%-100%=10%

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A polynomial has been factored, as shown below: f(x) = (x − 6)(x + 5)(x − 9) What are the zeros of the polynomial? (5 points)
soldi70 [24.7K]

<span>x=6</span>, <span>x=−5</span> or <span>x=9</span>

Explanation:

<span><span>f<span>(x)</span></span>=<span>(x−6)</span><span>(x+5)</span><span>(x−9)</span></span>

If all of the linear factors are non-zero, then so is their product <span>f<span>(x)</span></span>.

If any of the linear factors is zero, then so is their product <span>f<span>(x)</span></span>.

5 0
3 years ago
.…: need this answers.....
Leto [7]
Sorry, cannot just give you answers without your input.
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3 0
3 years ago
An office is divided into 8 cubicles. How many of the cubicles are carpeted if only 1/4 of the cubicles are carpeted?
Bas_tet [7]
1/4 of 8 is 2. So 2 of the cubicles are carpeted.
5 0
3 years ago
Read 2 more answers
Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!
LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

4 0
3 years ago
3(x + 4) = 3x + 12 solve for x
iris [78.8K]

Answer:

all real numbers.

Step-by-step explanation:

First, distribute 3 to all terms within the parenthesis:

3(x + 4) = 3(x) + 3(4) = 3x + 12

3x + 12 = 3x + 12

Because both sides are the same, your answer for x is "all real numbers".

~

8 0
3 years ago
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