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Ratling [72]
2 years ago
7

The middle school baseball team, the badgers won 20 games last year. This year they won 22 games. What is the percent increase o

f games won from last year to this year ?
Mathematics
1 answer:
viktelen [127]2 years ago
4 0

Answer:

22/20×100%=110%

110%-100%=10%

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Given A = {1, 3, 5, 7, 9}, B = {2, 4, 6, 8, 10}, C = {1, 5, 6, 7, 9}
andrey2020 [161]

Answer:

ummmm thats not even a question

Step-by-step explanation:

6 0
2 years ago
Use set notation to denote the elements, subsets, and complements of the following given sets.
vlabodo [156]

Answer:

N = {13, 15, 17, 19} is the correct answer.

Step-by-step explanation:

<u>We are given with the following details:</u>

N is the set of odd natural numbers.

N contains the elements which are greater than 11 and less than 21.

<u>To write:</u> The set notation for the elements of set N.

<u>Solution:</u>

First of all, let us see what are odd natural numbers.

Natural numbers are the positive integers i.e. {1,2,3,4, ........ }

Odd Natural numbers are the natural numbers which leave remainder as 1 when divided by 2 i.e. {1,3,5,7,9,11,13, ...... 21, 23, 25, 27.....}

Here, set N is odd natural numbers greater than 11 (so 11 will not be included) and less than 21 (so 21 will not be included). Odd natural numbers between 11 and 21 will be included.

So the <em>answer will be N = {13,15,17,19}.</em>

<em></em>

7 0
2 years ago
What is the inverse of the function f(x) = 2x – 10?
Lana71 [14]

Answer:

h(x)=\dfrac{x}{2}+5

Step-by-step explanation:

You are given the function f(x)=2x-10. To find the inverse function f^{-1}(x) do such steps:

1. Rewrite the function f(x) as

y=2x-10

2. Express x in terms of y:

y+10=2x\\ \\x=\dfrac{y}{2}+5

3. Change x into y and y into x:

y=\dfrac{x}{2}+5

Now, the inverse function is

f^{-1}(x)=\dfrac{x}{2}+5

7 0
3 years ago
Read 2 more answers
Complete the square to write the quadratic expression in vertex form.
Anvisha [2.4K]

Answer:

1. (x - 3)² = 8

2. (x + 2)² = 3

3. (x + 6)² = $ \frac{101}{2} $

4. (x + 3)² = 27

5. (x + 4)² = 13

6.  $ \bigg( x - \frac{15}{9} \bigg) ^2 = \frac{261}{81} = \frac{29}{9} $

Step-by-step explanation:

Completion of Square: $ (x - a) ^2 = x^2 - 2ax + a^2 $

In the following problems the terms in the RHS of the above equation may be missing. We balance the equation. Simplify it and re write it in terms of LHS.

1. x² - 6x + 1 = 0

Taking the constant term to the other side, we get:

x² - 6x = - 1

⇒ x² - 2(3)x = -1

⇒ x² -2(3)x + 9 = - 1 + 9  [Adding 9 to both the sides]

⇒ x² -2(3)x + 3² = 8

⇒ (x - 3)² = 8 is the answer.

2. 3x² + 12x + 3 = 0

Note that the co-effecient of x² is not 1. We make it 1, by dividing the whole equation by 3. And then proceed like the previous problem.

3x² + 12x = -3

Dividing by 3 through out, x² + 4x = - 1

⇒ x² + 2(2) + 4 = -1 + 4

⇒ x² +2(2) + 2² = 3

⇒ (x + 2)² = 3 is the answer.

3. 2x² + 24x = 29

x² + 12x = $ \frac{29}{2} $

⇒ x² + 2(6)x + 36 = $ \frac{29}{2} $ + 36

⇒ x² + 2(6)x + 6² = $ \frac{29 + 72}{2} $

⇒ (x + 6)² = $ \frac{101}{2} $ is the answer.

4. x² + 6x - 18 = 0

x² + 6x = 18

⇒ x² + 2(3)x = 18

⇒ x² + 2(3)x + 9 = 18 + 9

⇒ x² + 2(3)x + 3² = 27

⇒ (x + 3)² = 27 is the answer.

5. x² + 8x + 3 = 0

x² + 8x = -3

⇒ x² + 2(4)x = -3

⇒ x² + 2(4)x + 16 = - 3 + 16

⇒ x² + 2(4)x + 16 = 13

⇒ (x + 4)² = 13 is the answer.

6. 9x² - 30x + 6 = 0

9x² - 30x = - 6

⇒ x² $ - \frac{30}{9} $ x = - 6

$ \implies x^2 -2 \bigg( \frac{15}{9} \bigg )x + \frac{225}{81} = - 6 + \frac{225}{81} $

$ \implies x^2 - 2\bigg( \frac{15}{9} \bigg ) x + \bigg ( \frac{15}{9} \bigg ) ^2 = \frac{261}{81} $

$ \bigg( x - \frac{15}{9} \bigg) ^2 = \frac{261}{81} = \frac{29}{9} $ is the answer.

6 0
3 years ago
Consider a single spin of the spinner. Which events are mutually exclusive? Choose all that apply. a)landing on a shaded sector
denis23 [38]

Answer: the correct options are b and d.

Step-by-step explanation:

Let us first define what mutually exclusive events are. If two events are mutually exclusive, it means that they cannot happen at the same time. For example, getting a head and a tail at the same time are mutually exclusive.

Considering a single spin of the spinner, the events that are mutually exclusive are

b)landing on a shaded sector and landing on a 3. This is because 3 is unshaded. You can either land on 3 or an unshaded sector at a time

d)landing on an unshaded sector and landing on a number less than 2. This is because the numbers in the unshaded sectors are greater than 2.

3 0
3 years ago
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