twenty hundretdths is what I assume the answer is
Uhh me neither thats very complicated
Answer: 145 cans
Step-by-step explanation:
arithmetic sequence
aₙ = a₁ + (n-1).r
aₙ → last term
a₁ → 1st term
n → quantity of terms
r → common difference
a₁ = 1 (one can at the top)
aₙ₋₁ = 25
aₙ = 28
To find out How many cans are in the entire display, we need the SUM of the arithmetic sequence: S = (a₁+aₙ)n/2
∴
S = (1+28).n/2
n = ?
aₙ = a₁ + (n - 1).r
r = 28 - 25 = 3
28 = 1 + (n - 1).3
27 = (n - 1).3
27/3 = (n - 1)
9 = n - 1
n = 9 + 1 = 10
S = (1+28).n/2
S = (1+28).10/2 = 29.10/2 = 29.5 = 145
Answer:
3.1
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
