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3 years ago

I don’t really understand this

Mathematics

2 answers:

goldenfox [79]3 years ago

8 0

Answer:

Step-by-step explanation

Square root of 4 is 2

2/5 =0.4

Pi /5 = 3.142 ÷ 5 = 0.6284

3÷10 = 0.3

These are the figures you plot on the graph

mars1129 [50]3 years ago

7 0

Uhh me neither thats very complicated

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A balloon has a circumference of 28 in use the circumference to approximate the surface area of the ballon to the nearest square

nikklg [1K]

The surface area of the balloon is 249 in².

<h3>What is the surface area of the balloon ?</h3>

A balloon has the shape of a sphere. The distance round the sphere is equal to the circumference of the sphere.

Circumference of the sphere = 2πr

Where:

r = radius
π = pi = 22 / 7

Radius - circumference / 2π

28 / ( 2 x 22/7) = 4.45 inches

Surface area of a sphere = 4πr²

4 x 22/7 x 4.45² = 249 in²

To learn more about the surface area of a sphere, please check: brainly.com/question/27267844

#SPJ1

5 0

1 year ago

Plz help<br>urgent !!!!<br>will give the brainliest !!

Mkey [24]

Answer:

$X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}$

Step-by-step explanation:

The question we have at hand is, in other words,

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix}$ - where we have to solve for the value of $X$

If we have to isolate $X$ here, then we would have to take the inverse of the following matrix ...

$\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}$ ... so that it should be as follows ... $\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}$

Therefore, we can conclude that the equation as to solve for " $X$ " will be the following,

$X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ - First find the 2 x 2 matrix inverse of the first portion,

$\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}$ = $\frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}$ = $\frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix}$ = $\begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}$

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

$X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix}$ ,

$X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix}$ - Simplifying this, we should get ...