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Naily [24]
2 years ago
12

Just the answer please.

Mathematics
1 answer:
Bond [772]2 years ago
5 0

Answer:

No, they are not similar.

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Can someone help out?​
Tamiku [17]

Answer:

152.9 ft

Step-by-step explanation:

14*8=112

8*4=32

112+32+8.9=152.9

8 0
2 years ago
1 + tanx / 1 + cotx =2
Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

1/4 - tan(x) + tan^2(x) = -3/4

Write the left hand side as a square:

(tan(x) - 1/2)^2 = -3/4

Take the square root of both sides:

tan(x) - 1/2 = (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

tan(x) = 1/2 + (i sqrt(3))/2 or tan(x) - 1/2 = -(i sqrt(3))/2

Take the inverse tangent of both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

4 0
3 years ago
What is equivalent to (b+6)3?​
arlik [135]

3(b+6) = 3*b + 3*6 = 3b + 18

5 0
2 years ago
Juan builds this pedestal for a trophy. What is the volume of the pedestal? Enter your answer in the box. in³ Three-dimensional
Marrrta [24]
The answer is is negative 0
4 0
2 years ago
Help me out here please. find the area
Vinvika [58]

Answer: 56

Step-by-step explanation: first, you have to find the area of one triangle. The formula is A=bh1/2 . When you do that, you get 14. 14 is only one triangle, so multiply it by 4 and you get your answer, 56.

6 0
2 years ago
Read 2 more answers
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