So long as the perimeters are the same, rectangles and squares share the same area. For example, a square that is 2m by 2m across is 4m squared. A rectangle of 4m by 1m across is still 4m squared.
Therefore all we want to do here is see how big we can make our “square” perimeter using the creek. We have three sides to spread 580ft across, therefore if we divide this by 3, we get 193.3ft of fencing per side. If we then square this figure, we will then get the maximum possible area, which comes to 37,377ft squared. (That’s a huge garden).
Answer:
x ≈ 5.89
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra II</u>
- Exponential to Logarithmic:
![\displaystyle b^m=x \rightarrow log_bx=m](https://tex.z-dn.net/?f=%5Cdisplaystyle%20b%5Em%3Dx%20%5Crightarrow%20log_bx%3Dm)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
0.77 = log(x)
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Equality Property] Raise both sides to the 10th power:
![\displaysytle 10^{0.77} = 10^{logx}](https://tex.z-dn.net/?f=%5Cdisplaysytle%2010%5E%7B0.77%7D%20%3D%2010%5E%7Blogx%7D)
- Simplify:
![\displaysytle x = 10^{0.77}](https://tex.z-dn.net/?f=%5Cdisplaysytle%20x%20%3D%2010%5E%7B0.77%7D)
- Evaluate:
![\displaysytle x = 5.88844](https://tex.z-dn.net/?f=%5Cdisplaysytle%20x%20%3D%205.88844)
Answer:
B
Step-by-step explanation:
B and D are the only ones with the same slope (-3x) which is required for the line to be parallel.
and if you graph it out, you will find that B is the correct answer because it passes through (2,-4).
F(x + 1) = (5/2)*f(x)
f(x + 1) = 2.5*f(x), f(1) = 3.2
f(2) = 2.5f(1) = 2.5*3.2 = 8
<span>f(3) = 2.5f(2) = 2.5*8 = 20
</span>
f(4) = 2.5f(3) = 2.5*20 = 50
<span>f(5) = 2.5f(4) = 2.5*50 = 125</span>
The answer is 30
2 x 3 = 6
5 x 6 = 30