With a given parallel line and a given point on the line
we can use the point-line method: y-y0=m(x-x0)
where
y=mx+k is the given line, and
(x0,y0) is the given point.
Here
m=-10, k=-5, (x0,y0)=(-3,5)
=> the required line L is given by:
L: y-5=-10(x-(-3))
on simplification
L: y=-10x-30+5
L: y=-10x-25
Answer:
pretty good tired of the virus stuff but good
Step-by-step explanation:
Because AC is a diameter we can find the 180/3 = x
giving us the x= 60
Then that arc AB = 120
Answer:

Step-by-step explanation:

Answer:
will have a trillionare by that time
Step-by-step explanation: