Answer:
The power function can be written as a recursive function (using Java) as follows:
- static int power(int x, int n)
- {
- if(n == 0){
- return 1;
- }
- else {
- return power(x, n-1 ) * x;
- }
- }
Explanation:
A recursive function is a function that call itself during run time.
Based on the question, we know x to the 0th power is 1. Hence, we can just create a condition if n = 0, return 1 (Line 3 - 5).
Next, we implement the logic "x to the nth power can be obtained by multiplying x to the n-1'th power with x " from the question with the code: return power(x, n-1 ) * x in the else block. (Line 6 -8)
In Line 7, power() function will call itself recursively by passing x and n-1 as arguments. Please note the value of n will be reduced by one for every round of recursive call. This recursive call will stop when n = 0.
Just imagine if we call the function as follows:
int result = power(2, 3);
What happen will be as follows:
- run Line 7 -> return power(2, 2) * 2
- run Line 7 -> return power(2, 1) * 2
- run Line 7 -> return power(1, 0) * 2
- run Line 4 -> return 1 (Recursive call stop here)
Next, the return value from the inner most recursive call will be return to the previous call stack:
- power(1, 0) * 2 -> 1 * 2
- power(2, 1) * 2 -> 1 * 2 * 2
- power(2, 2) * 2 -> 1 * 2 * 2 * 2 - > 8 (final output)
Answer:
grad_age=matric_age+4
Explanation:
As mention in the question their are two variable matric_age and grad_age respectively .The grad_age variable store the value of 4 more than that of matric_age i.e (matric_age+4) means that it store the value 4 plus matric_age Suppose a matric_age is initialized with 4 then value of grad_age=4+4=8.
You can easily organize your work space. also you may have more resources. hope this helps
The process where the programmer steps through each of the program's statements one by one is called 
.
