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2 years ago

If the original quantity is 14 and the new quantity is 22, which of these is the best estimate for the percent of change?

Mathematics

1 answer:

julsineya [31]2 years ago

8 0

D 22-14=8 14-7=7 7 of 14=50% so i think that’s the best estimate

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For each of these relations on the set {21, 22, 23, 24}, decide whether it is reflexive, whether it is symmetric, whether it is

bonufazy [111]

Answer:

Step-by-step explanation:

I. { (22,22) , (22,23) , (22,24) , (23,22) , (23,23) , (23,24) }

Reflexive : True because we see the pairs (22,22) , (23,23)..

Symmetrix : NO, as we see the pairs (22,24) BUT NOT (24,22)

Transitive : YES, As we see (22,22 ) and (22, 24) , we see the pairs (22,24)

Antisymmetric : NO

II){ (21,21) , (21,22) , (22,21) , (22,22) , (23,23) , (24,24) }

Reflexive : True because we see the pairs (22,22) , (23,23) (21,21)

Symmetrix : Yes, as we see the pairs (21,22) AND (22,21)

Transitive : YES,

Antisymmetric : NO

7 0

3 years ago

Read 2 more answers

Which equation represents the graph of the linear function?

nirvana33 [79]

The y intercept in this graph is (0,1) ad the only equations that fit this are a and c.
To figure out whether it is a or c, find the slope. The line of the equation is going up, so he slope is positive. Equation c has the positive slope.
EQUATION C

5 0

3 years ago

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Given the sum s20= 910 of an arithmetic sequence and A20 = 95, Find A1

Inessa05 [86]

Step-by-step explanation:

Sn=n/2(2a+(n-1)d)

910=n/2{2a+(n-1)d}

1820=n{2a+(n-1)d}

1820=20{2a+(20-1)d}

1820=20{2a+19d}

91=2a+19d

An=a+(n-1)d

95=a+(20-1)d

95=a+19d

91=2a+19d

---------------

4=-a

a=-4

91=2a+19d

91=2(-4)+19d

91=-8+19d

91+8=19d

99=19d

d=99/19

A=-4

5 0

2 years ago

If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

3 years ago

This is for a grade and I’m so confused

arlik [135]

The answer is letter d because the y collum is y=y•2+1

8 0

2 years ago