3 years ago

If one latter is chosen at random from the word refuse, what is the probability that the letter chosen will be an "e"

1 answer:

3 0

2/6 there is 6 letters in the word "refuse" and two e's in the word "refuse".

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Maurinko [17]

Step-by-step explanation:

$h(x) = \frac{2}{3} x - 9$

$h( - 6) = \frac{2}{3} ( - 6) - 9$

$= - 4 - 9$

$= - 13$

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3 years ago

iren [92.7K]

Answer:

Hope that answers your question

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2 years ago

Aneli [31]

Answer:

Whats the question?

Step-by-step explanation:

or is it just like a fake question

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Advocard [28]

Answer: 484/5

Step-by-step explanation:

For this word problem, it seems confusing with the wording but the equation would just be:

968÷10=x

solving for x, we get 484/5.

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Yuliya22 [10]

50 brochures and 150 fliers with a cost of 10$

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