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swat32
3 years ago
12

If one latter is chosen at random from the word refuse, what is the probability that the letter chosen will be an "e"

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
3 0
2/6 there is 6 letters in the word "refuse" and two e's in the word "refuse".
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Based on the data provided, what is the expected cost of repairs over two years if each repair costs $60?
irina [24]
How many repairs a year?
6 0
3 years ago
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good moring yall anyone know how to do this i have a idea but i think im wrong so anyone want to clear that up for me?
AlexFokin [52]

Answer:

good morning :)

the answer is 15

Step-by-step explanation:

because jayda found 5 and ruby found twice as her which means he found 10 and all they are asking you to do is add jayda's and ruby's sheashells togather

hope this helps <333

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6 0
2 years ago
Given the following graph of a system of inequalities, the point (3, 2) _____________.
uysha [10]
That point does not satisfy either inequality. 

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5 0
3 years ago
Help
alisha [4.7K]

Answer:

a. x^{2}  + 3y^{3}

b. 3y^{3} -6

c. 5x -3

d. -6t - 5

Step-by-step explanation:

When a number has the same variable as another, you can add or subtract them

So for the first one, you can do

5x^{2} -4x^{2} = 1x^{2}  = x^{2}

(But don't forget the 3y^{3}!)

So it is:

x^{2}  + 3y^{3}

Continue this process for the rest of them

7 0
2 years ago
3 exponet 8×4+9÷1×56+57
nika2105 [10]
You would use PEMDAS

But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57

Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57

Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57

Now you can add all of the numbers together
32➕504=536
536➕57=593

Your answer is 593

Hope this helps! :3
4 0
3 years ago
Read 2 more answers
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