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marshall27 [118]
3 years ago
7

Phillip is mowing his backyard. His backyard is oddly shaped.

Mathematics
2 answers:
RSB [31]3 years ago
8 0
The answer is 336 square feet
salantis [7]3 years ago
3 0
106 square feet.. your welcome
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Given a sphere with a radius of 7.5 ft.
ad-work [718]

Answer:

volume of the sphere is  V=1766.25 ft^{3}

Step-by-step explanation:

step:1

<u>The volume of the sphere formula is V=\frac{4 pi r^{3}  }{n}</u>

<u>step:2</u>

Given radius of the sphere r=7.5 ft

substitute given radius r=7.5 ft value in volume of the sphere formula

V=[tex]\frac{4 pi r^{3}  }{n}\\

V=\frac{4(3.14)(7.5)^{3} }{3}[/tex]

V=1766.25 ft^{3}

Final answer is V=1766.25 ft^{3}

3 0
3 years ago
What is the value of c? <br><br> A. 34<br><br> B. 68<br><br> C. 38<br><br> D. 71
Maru [420]
The Value of C is 71
7 0
3 years ago
Read 2 more answers
Decompose x^2+4x-3/x-2​
mariarad [96]

Answer:

\dfrac{x^3-2x^2+4x-3}{x-2}

Step-by-step explanation:

The given equation is :

x^2+\dfrac{4x-3}{x-2}

We need to decompose this equation.

We have,

x^2+\dfrac{4x-3}{x-2}\\\\=\dfrac{x^2(x-2)+4x-3}{x-2}\\\\=\dfrac{x^3-2x^2+4x-3}{x-2}

So, \dfrac{x^3-2x^2+4x-3}{x-2} is the decomposed form of the given expression.

5 0
2 years ago
What is the length of side TS?
-Dominant- [34]
We know that

 in the triangle TQS
<span>applying the Pythagorean theorem
QS</span>²=TS²+TQ²---------> TQ²=QS²-TS²--------> TQ²=18²-9x²-----> equation 1

in the triangle TRS
TS²=TR²+RS²--------------> TR²=TS²-RS²-------> TR²=9x²-144----> equation 2

in the triangle QTR
TQ²=TR²+36-----------> equation 3


<span>I substitute 1 and 2 in 3
</span>18²-9x²=9x²-144+36--------> 18x²-432=0------> x²=24-------> x=√24
x=2√6
TS=3*x------> 3*2√6-----> 6√6
TS=6√6 units

the answer is
TS=6√6 units 
<span>6 is the square root of 6 units</span>
6 0
3 years ago
Read 2 more answers
What is the domain and range of the graph shown?​
marissa [1.9K]

Answer:

[0. infinity)

[0, infinity)

7 0
2 years ago
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