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guapka [62]
3 years ago
11

8. Use the ruler to measure the length of

Mathematics
1 answer:
koban [17]3 years ago
7 0

Answer:

6.1 , 6.1

Step-by-step explanation:

Trust

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A room has an area of 60 square meters and a perimeter of 32 meters. What are the length and width of the room?
Dominik [7]

Answer:

6 and 10

Step-by-step explanation:

xy=60

2(x+y)=32

x+y=16

y=16-x

Substitute y into area equation

x(16-x)=60

16x-x^2=60

x^2-16x+60=0

(x-10)(x-6)=0

x=10, 6

y=6, 10

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2 years ago
Which eqaution dosen't belong
kompoz [17]

Answer:

you need more info please

Step-by-step explanation:

8 0
3 years ago
chuck wants to increase his savings account by 45%. if chuck has230 in his account, how much will he have after increasing his s
katovenus [111]

Answer:

$333.5

Step-by-step explanation:

First we have to find 45% of 230 and then add that value to 230

(we can also find 145% of 230, which is essentially the same thing)

so 45% of 230 is:

230*(45/100)= $103.5

230+103.5= $333.5

4 0
3 years ago
If May was going to the prom and asked out 98 boys to go to the prom with her and 50% of the boys touched held her hand, made ey
tangare [24]

Answer:

49 boys did things that May liked

Step-by-step explanation:

May be getting aroundddd, she a real h o e

7 0
3 years ago
Read 2 more answers
Researchers at the National Cancer Institute released the results of a study that investigated the effect of weed-killing herbic
jolli1 [7]

Answer:

The 95% confidence interval for the difference in the proportion of cancer diagnoses between the two groups is (0.3834, 0.5166).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

The randomly sampled 400 dogs from homes where an herbicide was used on a regular basis, diagnosing lymphoma in 230 of them.

This means that:

p_h = \frac{230}{400} = 0.575, s_h = \sqrt{\frac{0.575*0.425}{400}} = 0.0247

Of 200 dogs randomly sampled from homes where no herbicides were used, only 25 were found to have lymphoma.

This means that:

p_n = \frac{25}{200} = 0.125, s_n = \sqrt{\frac{0.125*0.875}{200}} = 0.0234

Distribution of the difference:

p = p_h - p_n = 0.575 - 0.125 = 0.45

s = \sqrt{s_h^2+s_n^2} = \sqrt{0.0247^2 + 0.0234^2} = 0.034

Confidence interval:

The confidence interval is:

p \pm zs

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower bound is 0.45 - 1.96(0.034) = 0.3834

The upper bound is 0.45 + 1.96(0.034) = 0.5166

The 95% confidence interval for the difference in the proportion of cancer diagnoses between the two groups is (0.3834, 0.5166).

3 0
4 years ago
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