On average, she spent 18/36 = 0.5$
Answer:
Jessica Bradley - 856 Points
Tina Harner - 707 Points
Step-by-step explanation:
FULL QUESTION:
The highest scorer of the women's basketball championship was Jessica Bradley. She scored 149 more points than Tina Harner, her teammate. Together, Bradley and Harner scored 1563 points. How many points did each player score during the championship?
Let T = points scored by Tina Harner
J = points scored by Tina Harner
She scored 149 more points than Tina Harner, her teammate. This means;
J = T + 149...........(i)
Together, Bradley and Harner scored 1563 points. This means;
J + T = 1563 .........(ii)
How many points did each player score during the championship?
We have to find T and J.
Substitute value of J from eqn (i) into eqn (ii)
T + 149 + T = 1563
2T = 1563 - 149 = 1414
T = 1414 / 2 = 707
J = 707 + 149 = 856
Jessica Bradley - 856 Points
Tina Harner - 707 Points
Answer:
x=-50
Step-by-step explanation:
31/25x=-62
x=-62/(31/25)
x=(-62/1)(25/31)
x=--1550/31
x=-50
Answer:
2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So



has a pvalue of 0.7881.
1 - 0.7881 = 0.2119
So 21.19% of the students use the computer for longer than 40 minutes.
Out of 10000
0.2119*10000 = 2119
2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.
Answer:
The first is 30
Step-by-step explanation:
The third is 115