Answer:
![f(t) = 8400(1.0018)^{12t}](https://tex.z-dn.net/?f=f%28t%29%20%3D%208400%281.0018%29%5E%7B12t%7D)
2.22%
Step-by-step explanation:
$8400 is invested in an account earning 2.2% interest (APR), compounded monthly.
So, the value of the account after t years will be given by
{Rounded to the four decimal places} (Answer)
Now, for t = 1 year, f(1) = $8586.67
So, the percentage of growth per year (APY) =
% {Rounded to the nearest hundredth of percent} (Answer)
A dot above 7, 4, 10, 2, and 20. Draw a box around the median, first quartile, and and the third quartile. Then connect the box to the minimum and maximum by drawing a line. Should look like this:
Answer:
$18.50
Step-by-step explanation:
In the example before 61 messages = $6.10 or rounding to the tenths place 6.1. If you do the same with 185, you get 18.5 or 18.50
ANSWER
Vertical shift: 6 units up
Maximum value: 9
Minimum value: 3
EXPLANATION
The given since function is
![y = 3(2 - \sin(x))](https://tex.z-dn.net/?f=y%20%3D%203%282%20-%20%20%5Csin%28x%29%29)
Expand and rewrite to obtain,
![y = 6 - 3 \sin(x)](https://tex.z-dn.net/?f=y%20%3D%206%20-%203%20%5Csin%28x%29)
Or
![y =- 3 \sin(x) + 6](https://tex.z-dn.net/?f=y%20%3D-%203%20%5Csin%28x%29%20%2B%206)
The vertical shift is 6 units up.
The maximum value is 6+3=9.
The minimum value is -3+6=3
Answer:
865
Step-by-step explanation:
We have that in 95% confidence level the value of z has a value of 1.96. This can be confirmed in the attached image of the normal distribution.
Now we have the following formula:
n = [z / E] ^ 2 * (p * q)
where n is the sample size, which is what we want to calculate, "E" is the error that is 2% or 0.02. "p" is the probability they give us, 5 out of 50, is the same as 1 out of 10, that is 0.1. "q" is the complement of p, that is, 1 - 0.1 = 0.9, that is, the value of q is 0.9.
Replacing these values we are left with:
n = [1.96 / 0.02] ^ 2 * [(0.1) * (0.9)]
n = 864.36
865 by rounding to the largest number.