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n200080 [17]
3 years ago
12

Point G is the centroid of the right △ABC with hypotenuse AB=18 in. Find CG.

Mathematics
2 answers:
natita [175]3 years ago
5 0
<h3>Answer:</h3>

6 in

<h3>Explanation:</h3>

CG is 2/3 the length of median CM, where M is the midpoint of AB. M is the center of the circumscribing circle, which has radius 9 in, so CM is 9 in, and CG is 6 in.

Virty [35]3 years ago
4 0

Answer:

CG = 6 in.

Step-by-step explanation:

Given information : Point G is the centroid of the right △ABC with hypotenuse AB=18 in.

We know that circumcenter of a right angle triangle is the midpoint of the hypotenuse.

Let point M be the circumcenter of △ABC.

Hypotenuse AB=18 in.

Radius of circumcircle = \frac{18}{2}=9 in.

Know connect the circumcenter M with the vertex C. CM is a median of the △ABC from vertex C.

MC = radius of the circumcircle = 9 in.

We know that centroid divides each median in a ratio of 2:1.

Point G is the centroid of the right △ABC. It means point G divides CM median in a ratio of 2:1.

CG=9\times \frac{2}{3}=6

GM=9\times \frac{1}{3}=3

Therefore, the measure of CG is 6 in.

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It is defined as the four-sided polygon in geometry having four edges and four corners. Kite is quadrilateral, in which. Two pairs of congruent sides, and it has one pair of opposite congruent angles.

The figure is missing.

On a coordinate plane, kite WXYZ is shown (please refer to the picture)

We have a kite and the coordinates of the kite are:

Point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

Using the distance formula we can find the distance between coordinates:

\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

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\rm WX=\sqrt{(2+3)^2+(3-3)^2}

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Similarly, distance between X and Y:

XY = √53 units

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Perimeter = 5 + √53 + √53 + 5

Perimeter = (10 + 2√53)  units

Thus, the perimeter of the kite is (10 + 2√53) units if the kite and the coordinates of the kite are point W is at (-3, 3), point X is at (2, 3), point Y is at (4, -4), and point Z is at (-3, -2).

Learn more about the quadrilateral here:

brainly.com/question/6321910

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