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Jobisdone [24]
3 years ago
11

I don’t have a clue what this word is

Mathematics
2 answers:
bagirrra123 [75]3 years ago
5 0
My pp gargle hert at nite wen I pp
Naily [24]3 years ago
4 0
What word? Be more specific please
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Fernando will divide 0.24 by 4 to help him solve a math problem. Which model below could represent this math problem
balandron [24]

Answer:

So the model should represent either \frac{6}{100} or\frac{3}{50} (its equivalent and simplified form.

Step-by-step explanation:

1) Originally the question wants to represent this quotient as tiles.

So,\frac{\frac{24}{100}}{4} =\frac{24}{100} *\frac{1}{4} =\frac{6}{100}=

We can still simplify it, but since we're dealing with 100 x 100 squares let's keep it this way

2) So the model should represent either \frac{6}{100} or\frac{3}{50} (its equivalent and simplified form.

6 0
3 years ago
Graph the line y=-5/3x-1
Pepsi [2]

Answer:

Put a dot on -1. Go down 5 and then 3 to the right. You will have two points which is enough to make a line. Grab a ruler and connect both of them. You have the line y=-5/3x-1 graphed


Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
Find the product.<br> (x-2) (x-3)
ivann1987 [24]

Answer:

Expand the polynomial using the FOIL method.

x2-5x+6

Step-by-step explanation:

happy to help.

4 0
3 years ago
Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap
vodomira [7]

Answer:

<h2> 0.0526ft/min</h2>

Step-by-step explanation:

Since the gravel being dumped is in the shape of a cone, we will use the formula for calculating the volume of a cone.

Volume of a cone V = πr²h/3

<em>If the diameter and the height are equal, then r = h</em>

V = πh²h/3

V = πh³/3

If the gravel is being dumped from a conveyor belt at a rate of 20 ft³/min, then dV/dt = 20ft³/min

Using chain rule to get the expression for dV/dt;

dV/dt = dV/dh * dh/dt

From the formula above, dV/dh = 3πh²/3

dV/dh =  πh²

dV/dt = πh²dh/dt

20 = πh²dh/dt

To calculate how fast the height of the pile is increasing when the pile is 11 ft high, we will substitute h = 11 into the resulting expression and solve for dh/dt.

20 = π(11)²dh/dt

20 = 121πdh/dt

dh/dt = 20/121π

dh/dt = 20/380.133

dh/dt = 0.0526ft/min

This means that the height of the pile is increasing at  0.0526ft/min

3 0
3 years ago
What is the length of line segment S T if S is at -5,-1 and T is at -1,12? Round to the nearest hundredth.
GuDViN [60]
Distance formula : d = sqrt (x2 - x1)^2 + (y2 - y1)^2
(-5,-1)(-1,12)

d = sqrt (-1-(-5)^2 + (12 - (-1)^2
d = sqrt (-1 + 5)^2 + (12 + 1)^2
d = sqrt (4^2) + (13^2)
d = sqrt (16 + 169)
d = sqrt 185
d = 13.60 <==
4 0
3 years ago
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