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3 years ago

Write the word sentence as an equation. Then solve the equation.

Mathematics

2 answers:

Nana76 [90]3 years ago

6 0

Answer:

x/-9 = -16 ; 144

Step-by-step explanation:

x is the variable for "a number". It is being divided by -9, so x must be divided by -9. The number divided by -9 equals -16, so -16 must go on the other side of the equation. To solve, multiply both sides by -9 to cancel out the fraction and isolate the variable.

Eduardwww [97]3 years ago

5 0

Answer:

a/-9= -16

-16*-9=a

a= 144

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30 points: Answer the questions in the picture provided

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bigger thing.

6). Henri Becquerel is credited with discovering radioactivity.

7). The names of Madame Marie and Mssr. Pierre Curie were
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3 years ago

Solve for x if the angles are 110 and 2x+3

katen-ka-za [31]

Answer:

x=16

Step-by-step explanation:

Because this is an isosceles triangle the angle 2x+3 is the same as the missing angle. The angles in triangles add up to 180 degrees. 180-110=70.

Because the two angles are the same you can divide 70 by 2 to get 35.

35=2x+3.

35-3=2x+3-3

32=2x

32/2=2x/2

16=x

7 0

3 years ago

Read 2 more answers

ONLY SERIOUS ANSWERS!!!! 25 POINTS

AveGali [126]

Answer:

FD≈25.94.. rounded = 26

Step-by-step explanation:

FD²=12²+(4x+11)²

FD²=144+16x²+88x+121

FD²=265+16x²+88x

also

FD²=12²+(13x-16)²

FD²=144+169x²-416x+256

FD²=400+169x²-416x

thus

265+16x²+88x = 400+169x²-416x

16x²-169x²+88x+416x+265-400 = 0

-153x²+504x-135 = 0

we will solve this quadratic equation by suing the quadratic formula to find x

x=(-504±sqrt(504²-4(-153)(-135)))/2(-153)

x=(-504± $\sqrt{504^{2}-4(-153)(-135) }$ )/2(-153)

x=(-504± $\sqrt{254016-82620 }$ )/-306

x=(-504± $\sqrt{171396}$ )/-306

x=(-504±414)/-306

x=(-504+414)/-306 and x=(-504-414)/-306

x=-90/-306 and x=-918/-306

x= 5/17 , 3

substituting x by the roots we found

check for 5/17:

4x+11 = 4×(5/17)+11 = (20/17)+11 = (20+187)/17 = 207/17 ≈ 12.17..

13x-16 = 13×(5/17)-16 = (65/17)-16 = (65-272)/17 = -207/17 ≈ -12.17..

check for 3:

4x+11 = 4×3+11 = 12+11 = 23

13x-16 = 13×3-16 = 23

thus 3 is the right root

therfore

ED=23 and CD=23

FD²=FE²+ED² or FD²=FC²+CD²

FD²=12²+23²

FD²=144+529

FD²=673

FD=√673

FD≈25.94.. rounded = 26

5 0

3 years ago

Read 2 more answers

Which of the following has a slope of -3 and a y-intercept of -4?

tresset_1 [31]

The correct answer is C

6 0

3 years ago

The size of the left upper chamber of the heart is one measure of cardiovascular health. When the upper left chamber is enlarged

Temka [501]

Answer:

a) 0.283 or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z= $\frac{X-M}{s}$ where

X is the left atrial diameter value we are looking for its z-score

M is the mean left atrial diameter of healthy children (26.7 mm)

s is the standard deviation (4.7 mm)

Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*= $\frac{24-26.7}{4.7}$ ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*= $\frac{32-26.7}{4.7}$ ≈ 1.128

1-P(z<1.128)=0.8703=0.130

c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)= $\frac{30-26.7}{4.7}$ ≈ 0.702

z(25)= $\frac{25-26.7}{4.7}$ ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84= $\frac{X-26.7}{4.7}$ solving this equation for X we get X=30.648

5 0

3 years ago