Answer:
C
Step-by-step explanation:
Answer:
1. S(1) = 1; S(n) = S(n-1) +n^2
2. see attached
3. neither
Step-by-step explanation:
1. The first step shows 1 square, so the first part of the recursive definition is ...
S(1) = 1
Each successive step has n^2 squares added to the number in the previous step. So, that part of the recursive definition is ...
S(n) = S(n-1) +n^2
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2. See the attachment for a graph.
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3. The recursive relation for an arithmetic function is of the form ...
S(n) = S(n-1) +k . . . . . for k = some constant
The recursive relation for a geometric function is of the form ...
S(n) = k·S(n-1) . . . . . . for k = some constant
The above recursive relation is not in either of these forms, so it is neither geometric nor arithmetic.
Answer: just use photomath
Step-by-step explanation:
Answer:
1250
Step-by-step explanation:
that's what I got please let me know if I'm correct
Answer:
1. 8 p^19
2. -x^8
3. -2y^14
Step-by-step explanation:
1. 8p^15·(–p)^4
We can separate things inside the powers (ab)^x = a^x * b^x
8 p^15 * (-1)^4 p^4
We can add the exponents when the bases are the same x^a * x^b = x^(a+b)
8 p^ (15+4)
8 p^19
2.(-2x^2)^2*(-.25x^4)
We can separate things inside the powers (ab)^x = a^x * b^x
(-2)^2 (x^2)^2 (-1/4) x^4
4 x^4 -1/4 x^4
We can add the exponents when the bases are the same x^a * x^b = x^(a+b)
4 * -1/4 x^ (4+4)
-x^8
3.((-.5)y^4)^3*(16y^2)
We can separate things inside the powers (ab)^x = a^x * b^x
(-1/2) ^3 (y^4) ^3 (16) y^2
When a power is raised to a power, we multiply x^a^b = x^(ab)
-1/8 * y^(4*3) * 16 y^2
-1/8 *16 y^12 * y^2
We can add the exponents when the bases are the same x^a * x^b = x^(a+b)
-2 y^(12+2)
-2y^14
