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3 years ago

HELP PLEASE THESE ARE DUE TODAY

Mathematics

1 answer:

strojnjashka [21]3 years ago

6 0

I would say that the median is the best measure for the center as there are two major outliers (16 and 18)

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What is the point slope equation of the line that has a slope of -5 and goes through the points (-4,9)

pshichka [43]

The equation for the point-slope form is y - y1= m(x-x1), where m is the slope. Using the coordinates and slope given, y - 9 = -5(x-(-4)), which simplifies to
y - 9 = -5(x + 4)

6 0

3 years ago

The scatter plot for which type of data is most likely to suggest a linear association between

chubhunter [2.5K]

Answer:

level of water in a reservoir each....

Step-by-step explanation:

4 0

3 years ago

The school store sells erasers for $0.35 each and pencils for $0.15 each. Anthony spent $2.80 to buy a total of 12 erasers and p

Sergio039 [100]

Answer:

5 erasers.

Step-by-step explanation:

0.35e + 0.15p = 2.80

e + p = 12

e = 12 - p

0.35(12 - p) + 0.15p = 2.80

4.2 - 0.35p + 0.15p = 2.80

4.2 - 0.2p = 2.80

-0.2p = -1.4

-0.2p/-0.2p = -1.4/-0.2

p = 7

e = 12 - 7

e = 5

4 0

3 years ago

Which statement about the function f(x)=|x+3| is true?

Stels [109]

The given function f(x) = |x + 3| has both an absolute maximum and an absolute minimum.

What do you mean by absolute maximum and minimum ?

A function has largest possible value at an absolute maximum point, whereas its lowest possible value can be found at an absolute minimum point.

It is given that function is f(x) = |x + 3|.

We know that to check if function is absolute minimum or absolute maximum by putting the value of modulus either equal to zero or equal to or less than zero and simplify.

So , if we put |x + 3| = 0 , then :

± x + 3 = 0

±x = -3

So , we can have two values of x which are either -3 or 3.

The value 3 will be absolute maximum and -3 will be absolute minimum.

Therefore , the given function f(x) = |x + 3| has both an absolute maximum and an absolute minimum.

Learn more about absolute maximum and minimum here :

brainly.com/question/17438358

#SPJ1

5 0

1 year ago

Find the mass and center of mass of the lamina that occupies the region D and has the given density function rho. D is the trian

Alla [95]

Answer: mass (m) = 4 kg

center of mass coordinate: (15.75,4.5)

Step-by-step explanation: As a surface, a lamina has 2 dimensions (x,y) and a density function.

The region D is shown in the attachment.

From the image of the triangle, lamina is limited at x-axis: 0≤x≤2

At y-axis, it is limited by the lines formed between (0,0) and (2,1) and (2,1) and (0.3):

Points (0,0) and (2,1):

y = $\frac{1-0}{2-0}(x-0)$

y = $\frac{x}{2}$

Points (2,1) and (0,3):

y = $\frac{3-1}{0-2}(x-0) + 3$

y = -x + 3

Now, find total mass, which is given by the formula:

$m = \int\limits^a_b {\int\limits^a_b {\rho(x,y)} \, dA }$

Calculating for the limits above:

$m = \int\limits^2_0 {\int\limits^a_\frac{x}{2} {2(x+y)} \, dy \, dx }$

where a = -x+3

$m = 2.\int\limits^2_0 {\int\limits^a_\frac{x}{2} {(xy+\frac{y^{2}}{2} )} \, dx }$

$m = 2.\int\limits^2_0 {(-x^{2}-\frac{x^{2}}{2}+3x )} \, dx }$

$m = 2.\int\limits^2_0 {(\frac{-3x^{2}}{2}+3x)} \, dx }$

$m = 2.(\frac{-3.2^{2}}{2}+3.2-0)$

m = 2(-4+6)

m = 4

Mass of the lamina that occupies region D is 4.

Center of mass is the point of gravity of an object if it is in an uniform gravitational field. For the lamina, or any other 2 dimensional object, center of mass is calculated by:

$M_{x} = \int\limits^a_b {\int\limits^a_b {y.\rho(x,y)} \, dA }$