Answer:
f'(x) > 0 on
and f'(x)<0 on
Step-by-step explanation:
1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:

To find its decreasing interval :

2) Then let's find the critical point of this function:
![f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Cfrac%7B%5Cmathrm%7Bd%7D%20%7D%7B%5Cmathrm%7Bd%7D%20x%7D%5B6-2%5E%7B2x%7D%5D%3D%5Cfrac%7B%5Cmathrm%7Bd%7D%20%7D%7B%5Cmathrm%7Bd%7Dx%7D%5B6%5D-%5Cfrac%7B%5Cmathrm%7Bd%7D%7D%7B%5Cmathrm%7Bd%7Dx%7D%5B2%5E%7B2x%7D%5D%3D0-%5Bln%282%29%2A2%5E%7B2x%7D%2A%5Cfrac%7B%5Cmathrm%7Bd%7D%7D%7B%5Cmathrm%7Bd%7Dx%7D%5B2x%5D%3D-ln%282%29%2A2%5E%7B2x%7D%2A2%3D-ln2%2A2%5E%7B2x%2B1%5CRightarrow%20%7Df%27%28x%29%3D-ln%282%29%2A2%5E%7B2x%7D%2A2%5C%5C-ln%282%29%2A2%5E%7B2x%2B1%7D%3D-2x%5E%7B2x%7D%28ln%28x%29%2B1%29%3D0)
2.2 Solving for x this equation, this will lead us to one critical point since x' is not defined for Real set, and x''
≈0.37 for e≈2.72

3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.
Complete Question:
Jamie used the distributive property to find the product of s(t) and h(t). His work was marked incorrect. Identify Jamie's mistake. What advice would you give Jamie to avoid this mistake in the future?
s(t)•h(t)= (3x-4)(2x-8)
= 6x² - 24x -8x - 32
= 6x² - 32x - 32
Answer:
Jamie made a mistake in his second line (6x² - 24x -8x - 32), by wrongly multiplying the operation signs. The last term should be +32, not -32.
Advice: Jamie should take note of the rule that applies when multiplying signs.
Step-by-step Explanation::
To find out where exactly Jamie made mistake, let's find the product of the given functions, step by step:
s(t)•h(t)= (3x-4)(2x-8)
Using distributive property, do the following:


(this is where Jamie made mistake. -4 * -8 = +32. NOT -32.)
Add like terms

Jamie made a mistake in multiplying negative × negative. The last term in "6x² - 24x -8x - 32", should be +32. Negative × negative = +.
Therefore, it is advisable for Jamie to always take note of the rule that applies when multiplying signs.
The length of BC is 4.674 m
<u>Explanation:</u>
Given:
Angle A = angle B = 90°
AD = 2.1 m
AB = 1.9 m
CD= 3.2 m
An image is inserted for the reference
According to the figure,
a is the base
b is the height
c is the hypotenuse
Using pythagoras theorm:
a² + b² = c²
a² + (1.9)² = (3.2)²
a² + 3.61 = 10.24
a² = 6.63
a = 2.574
BC = 2.1 + 2.574
BC = 4.674m
Therefore, the length of BC is 4.674 m
Answer: there are no solutions
Step by step: Step 1: Simplify both sides of the equation.
3
(
x
−
1
)
=
5
x
+
3
−
2
x
(
3
)
(
x
)
+
(
3
)
(
−
1
)
=
5
x
+
3
+
−
2
x
(Distribute)
3
x
+
−
3
=
5
x
+
3
+
−
2
x
3
x
−
3
=
(
5
x
+
−
2
x
)
+
(
3
)
(Combine Like Terms)
3
x
−
3
=
3
x
+
3
3
x
−
3
=
3
x
+
3
Step 2: Subtract 3x from both sides.
3
x
−
3
−
3
x
=
3
x
+
3
−
3
x
−
3
=
3
Step 3: Add 3 to both sides.
−
3
+
3
=
3
+
3
0
=
6
Count the amount of digits from right to left:
The digit 5 appears at the eighth position.
Remember that the 7th position is for millions. So, the eighth position is for ten millions.
Therefore, the place where the digit 5 sits in the number 952,832,744 is ten millions.