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kupik [55]
3 years ago
7

Help on this question please. What is the perimeter of ABC?

Mathematics
2 answers:
mestny [16]3 years ago
8 0

Answer:

Step-by-step explanation

5x2=10

3x2=6

2x2=4

the answer would be 20

laiz [17]3 years ago
5 0
Answer:
20

I got this answer because I saw one just like this a few seconds ago and they got it right
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Use the given equation to determine if the points in the brackets are on the graph
dmitriy555 [2]

The points in the brackets are on the graph are (0, 2) and (6, 10)

<h3>How to determine if the points in the brackets are on the graph?</h3>

The equation of the line is given as

4x - 3y = -6

The points are given as:

{(0,2),(1,3),(4,7),(6,10)}

Rewrite as

(x, y) = {(0,2),(1,3),(4,7),(6,10)}

Next, we substitute the x and y values in the equation 4x - 3y = -6

So, we have

(0, 2):

4(0) - 3(2) = -6

-6 = -6 ---- true

(1, 3):

4(1) - 3(3) = -6

-5 = -6 ---- false

(4, 7):

4(4) - 3(7) = -6

-5 = -6 ---- false

(6, 10):

4(6) - 3(10) = -6

-6 = -6 ---- true

Hence, the points in the brackets are on the graph are (0, 2) and (6, 10)

Read more about linear equations at:

brainly.com/question/2226590

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3 0
1 year ago
PLEASE HELP MEEEEE
ElenaW [278]

Answer:

  t ≥ -12

Step-by-step explanation:

Divide the inequality by the coefficient of t. Because that value is negative, the sign gets reversed.

  (-4t)/(-4) ≥ (48)/(-4)

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5 0
3 years ago
Help math question derivative!
atroni [7]
Let f(x)=\sec^{-1}x. Then \sec f(x)=x, and differentiating both sides with respect to x gives

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Now, when x=\sqrt2, you get

(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}

You have \sec^{-1}\sqrt2=\dfrac\pi4, so \sec\left(\sec^{-1}\sqrt2\right)=\sqrt2 and \tan\left(\sec^{-1}\sqrt2\right)=1. So (\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}
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3 years ago
In a test of physical fitness, a group of men ages 65 and older from a local retirement community were told to do as many sit-up
Ivahew [28]
Give ten fifth teen twenty so...98
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3 years ago
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Alona [7]
It is the first answer choice
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2 years ago
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