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Allisa [31]
3 years ago
15

Find the zeros of the function. Enter the solutions from least to greatest. f(x)=-3x^2+75

Mathematics
2 answers:
maksim [4K]3 years ago
6 0

Answer:

Step-by-step explanation:

-5

5

Travka [436]3 years ago
6 0

Answer:

-5 and 5

Step-by-step explanation:

I used a graphing program to graph the function.

The x-intercepts of the graph are (-5, 0) and (5,0).

The zeros of the function are -5 and 5.

Hope this helps.

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yanalaym [24]

Answer:

3m = $30

Step-by-step explanation:

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3 years ago
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If a cow has a mass of 9 × 10^2
kotykmax [81]

Answer:

a) The blue whale has about 200 times more mass

Step-by-step explanation:

(blue whale mass)/(cow mass) = (1.8×10^5 kg)/(9×10^2 kg)

... = (1.8/9)×10^(5-2)

... = 0.2×10^3

... = 200

The blue whale has about 200 times as much mass as a cow.

5 0
4 years ago
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17. Does this graph below represent a linear or nonlinear function? ^^
TiliK225 [7]

Answer:linear

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The numbers are going up at the same rate and it’s a straight line

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3 years ago
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If a town with a population of 5,000 doubles in size every 11 years, what will the population be 44 years from now?
Akimi4 [234]
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8 0
3 years ago
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2. On the Internet, you find an Latin quiz with 10 matching vocabulary questions. Your 3 year old niece randomly matches the
DanielleElmas [232]

Answer:

Assume that there is a Latin quiz with 10 matching vocabulary questions, and your niece try to match them randomly. Then, the probability that she gets the first item right is

1

10

since there is only one correct answer for this item out of 10 options. Now, the probability that she gets the second item right is

1

9

since there is only one correct option and there is only 9 options left to choose from. So, in a similar fashion, the probability that she will get the third item correct is

1

8

, the fourth item correct is

1

7

and so on. Therefore, the probability that she will match them all correctly (getting a 100 on the quiz) is equal to

1

10

⋅

1

9

⋯

1

2

⋅

1

1

=

1

10

!

=

1

3628800

8 0
3 years ago
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