Find the vertices and foci of the hyperbola with equation quantity x plus 4 squared divided by 9 minus the quantity of y minus 5
squared divided by 16 = 1
1 answer:
Answer:
Vertices at (-7, 5) and (-1, 5).
Foci at (-9, 5) and (1,5).
Step-by-step explanation:
(x + 4)²/9 - (y - 5)²/16 = 1
The standard form for the equation of a hyperbola with centre (h, k) is
(x - h²)/a² - (y - k)²/b² = 1
Your hyperbola opens left/right, because it is of the form x - y.
Comparing terms, we find that
h = -4, k = 5, a = 3, y = 4
In the general equation, the coordinates of the vertices are at (h ± a, k).
Thus, the vertices of your parabola are at (-7, 5) and (-1, 5).
The foci are at a distance c from the centre, with coordinates (h ± c, k), where c² = a² + b².
c² = 9 + 16 = 25, so c = 5.
The coordinates of the foci are (-9, 5) and (1, 5).
The Figure below shows the graph of the hyperbola with its vertices and foci.
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