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3 years ago

Find the percent of change. Label increase or decrease. Round to the nearest tenth of a percent

Mathematics

2 answers:

notka56 [123]3 years ago

8 0

Answer:

0.15% decrease

Step-by-step explanation:

18.75 - 18.60 = 0.15

Hope this helped!

katrin2010 [14]3 years ago

3 0

The answer is 0.15% decrease

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Determine the equation for the parabola graphed below

Elza [17]

Answer:

$y=(x-2)^2-1$

Step-by-step explanation:

The given function:

Since the function is open upwards means is of $y=x^2$

And we can see one unit down and 2 units shifted on right in parent function.

Therefore, the function is of $y=(x-2)^2-1$

Graph takes parabola shape by quadratic function.

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3 years ago

The volume of a cylinder is 1323pi cmcubed. The radius of the base of the cylinder is 7 cm. What is the height of the cylinder?

Taya2010 [7]

V of cylinder = πr²h
h=V /(πr²)
h=27/π -exact value
h=1323/(3.14*(7)²)= 8.6 cm - approximate value

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3 years ago

Write the ratio in the simplest form 25 to 45

Bond [772]

Answer: 5/9 is the simplified fraction for 25/45 by using the GCD or HCF method. Thus, 5/9 is the simplified fraction for 25/45 by using the prime factorization method.

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2 years ago

Use the quadratic formula to solve for the roots in the following equation. 4x 2 + 5x + 2 = 2x 2 + 7x – 1

Natali5045456 [20]

Answer:

So, The roots are $x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}$

Step-by-step explanation:

$4x^2 + 5x + 2 = 2x^2 + 7x - 1$

We need to solve the equation to find the roots using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Rearranging the above equation:

$4x^2 -2x^2+ 5x-7x + 2+1 =0$

$2x^2 -2x + 3 =0$

Where a =2 , b=-2 and c =3 Putting values in quadratic equation and solving:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-2)\pm\sqrt{(-2)^2-4(2)(3)}}{2(2)}\\x=\frac{2\pm\sqrt{4-24}}{4}\\x=\frac{2\pm\sqrt{-20}}{4}\\\sqrt{-20} \,\,can\,\,be\,\, written\,\, as\,\, 2\sqrt{-5}\\ x=\frac{2\pm2\sqrt{-5}}{4}\\x=\frac{2+2\sqrt{-5}}{4} \,\, and \,\, x=\frac{2-2\sqrt{-5}}{4}\\x=\frac{2(1+\sqrt{-5})}{4} \,\, and \,\, x=\frac{2(1-\sqrt{-5})}{4}\\ x=\frac{1+\sqrt{-5}}{2} \,\, and \,\, x=\frac{1-\sqrt{-5}}{2}\\As \,\,we\,\, know\,\, \sqrt{-1} = i \\$

$x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}$

So, The roots are $x= \frac{1+\sqrt{5}i}{2} \,\, and \,\,x= \frac{1-\sqrt{5}i}{2}$

6 0

3 years ago

-m + 5n = -2, for n <br>

MakcuM [25]

Answer:

Step-by-step explanation:

-m + 5n = -2, for n

-m + 5n = -2

-m +5n + m = -2 + m

5n = m - 2

5n/5 = (m-2)/5

n = 1/5m + (-2)/5

6 0

2 years ago