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3 years ago

Please help me with this problem can you please show step by step on how you got the answer..

Mathematics

1 answer:

zhenek [66]3 years ago

7 0

Answer:

Yes

Step-by-step explanation:

To find the volume of something you use lengthxwidthxheight. 5x2x4 is equal to 10x4 which is equal to 40. Since the minimum is 35, this will meet the requirement.

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Answer:

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3 years ago

F(x)=2x^2+1 using the derivate definition

morpeh [17]

$\bf \stackrel{\textit{de} \textit{finition of a derivative as a limit}}{\lim\limits_{h\to 0}~\cfrac{f(x+h)-f(x)}{h}}\\\\
-------------------------------\\\\
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\\\\\\
\lim\limits_{h\to 0}~\cfrac{[2(x^2+2xh+h^2)+1]~~-~~[2x^2+1]}{h}
\\\\\\
\lim\limits_{h\to 0}~\cfrac{[2x^2+4xh+2h^2+1]~~-~~[2x^2+1]}{h}$

$\bf \lim\limits_{h\to 0}~\cfrac{\underline{2x^2}+4xh+2h^2\underline{+1}~~~~\underline{-2x^2-1}}{h}\implies \lim\limits_{h\to 0}~\cfrac{4xh+2h^2}{h}
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3 0

4 years ago

I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find

VARVARA [1.3K]

Answer:

mRP = 125°

mQS = 125°

mPQR = 235°

mRPQ = 305°

Step-by-step explanation:

Given that

mROP = 125°

∠ROP is a central angle

Then:

measure of arc RP, mRP = mROP = 125°

Given that

∠QOS and ∠ROP are vertical angles

Then:

mQOS = mROP = 125°

measure of arc QS, mQS = mROP = 125°

Given that

∠QOR and ∠SOP are vertical angles

Then:

mQOR = mSOP

Given that

The addition of all central angles of a circle is 360°

Then:

mQOS + mROP + mQOR + mSOP = 360°

250° + 2mQOR = 360°

mQOR = (360°- 250°)/2

mQOR = mSOP = 55°

And (QOR and SOP are central angles):

measure of arc QR, mQR = mQOR = 55°

measure of arc SP, mSP = mSOP = 55°

Finally:

measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°

measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°

6 0

3 years ago