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denis23 [38]
2 years ago
15

A teenager earns $10 for every 600 square feet mowed in addition to $12 for supplies for each lawn he mows. Which function repre

sents y, the teenager’s pay when he mows a lawn that is x square feet in size?
y = 10x + 600
y = 10x + 12
y = 1/60x + 12
y = 1/60x + 1/60
Mathematics
1 answer:
anzhelika [568]2 years ago
5 0

Answer: b

Step-by-step explanation: 600 is the total so, just do 10x and 12

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HELP ASAP
tia_tia [17]
2,700 / 12 = 225
225 / 5 = 45
They can make 45 necklaces.








3 0
3 years ago
write a system of linear equations that has only one solution. solve the system of equations in two ways.
Iteru [2.4K]
X + 5y = 1 . . . . (1)
8x - 2y = 3 . . . .(2)
Solution 1.
From (1), x = 1 - 5y
substituting for x in (2), we have:
8(1 - 5y) - 2y = 3
8 - 40y - 2y = 3
8 - 42y = 3
42y = 5
y = 5/42
x = 1 - 5(5/42) = 1 - 25/42 = 17/42.

Solution 2.
Multiply (1) by 8, to get:
8x + 40y = 8 . . . . . (3)
(3) - (2) = 40y - (-2y) = 8 - 3
42y = 5
y = 5/42
substitute for y into (3), to get:
8x + 40(5/42) = 8
8x + 100/21 = 8
8x = 8 - 100/21 = 68/21
x = (68/21)/8 = 17/42
7 0
3 years ago
Reduce a)95/75 b) 250/750 to its simplest form
umka21 [38]

Answer:

a) 19/15 b) 1/3

Step-by-step explanation:

in both the question I reduced the numbers with 5

8 0
2 years ago
Choose the correct conic section to fit the equation.
yanalaym [24]

Answer:

Option A) Circle.

Step-by-step explanation:

We are given the equation:

(x - 3)^2 + (y - 12)^2 = 25

A general equation of the circle is of the form:

(x-h)^2 + (y-k)^2 = r^2

where (h,k) is the center of the circle and r is the radius of circle.

Comparing the two equations, we get,

(h,k) = (3,12)\\r = \sqrt{25} = 5

Thus, the given equation is equation of a circle centered at (3,12) and of radius 5 units.

5 0
3 years ago
Select the correct answer.
Crazy boy [7]

check the picture below.

now, if we split that triangle like so with that red line, we can use the right-triangle there, to get θ.


\bf tan(\theta )=\cfrac{\stackrel{opposite}{3}}{\stackrel{adjacent}{3}}\implies tan(\theta )=1\implies tan^{-1}(\theta )=tan^{-1}(1)\implies \measuredangle \theta =\cfrac{\pi }{4}

8 0
3 years ago
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