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sergey [27]
3 years ago
6

I NEED ANSWER ASAP!!!! AND PLEASE GIVE ANSWER ACCORDING TO THE GRAPH BELOW :)))

Mathematics
1 answer:
podryga [215]3 years ago
5 0

Answer:

ok so put one point on (0, 1) and another on (3, -3)

brainliest pls :)

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The amounts of time per workout an athlete uses a stairclimber are normally​ distributed, with a mean of 24 minutes and a standa
Elodia [21]

Answer:

(a) The probability that a randomly selected athlete uses a stairclimber for​  less than 19 ​minutes is 0.2388.

(b) The probability that a randomly selected athlete uses a stairclimber for​  between 24 and 33 ​minutes is 0.3997.

(c) The probability that a randomly selected athlete uses a stairclimber for​  more than 40 minutes is 0.0113.

Step-by-step explanation:

We are given that the amounts of time per workout an athlete uses a stairclimber are normally​ distributed, with a mean of 24 minutes and a standard deviation of 7 minutes.

Let X = <u><em>amounts of time per workout an athlete uses a stairclimber</em></u>

So, X ~ Normal(\mu=24,\sigma^{2} =7^{2})

The z-score probability distribution for the normal distribution is given by;

                               Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = mean time = 24 minutes

            \sigma = standard deviation = 7 minutes

(a) The probability that a randomly selected athlete uses a stairclimber for​  less than 19 ​minutes is given by  P(X < 19 minutes)

        P(X < 19 min) = P( \frac{X-\mu}{\sigma} < \frac{19-24}{7} ) = P(Z < -0.71) = 1 - P(Z \leq 0.71)

                                                           = 1 - 0.7612 = <u>0.2388</u>

The above probability is calculated by looking at the value of x = 0.71 in the z table which has an area of 0.7612.

(b) The probability that a randomly selected athlete uses a stairclimber for​  between 24 and 33 ​minutes is given by = P(24 min < X < 33 min)

     P(24 min < X < 33 min) = P(X < 33 min) - P(X \leq 24 min)

     P(X < 33 min) = P( \frac{X-\mu}{\sigma} < \frac{33-24}{7} ) = P(Z < 1.28) = 0.8997

     P(X \leq 24 min) = P( \frac{X-\mu}{\sigma} \leq \frac{24-24}{7} ) = P(Z \leq 0) = 0.50

The above probability is calculated by looking at the value of x = 1.28 and x = 0 in the z table which has an area of 0.8997 and 0.50 respectively.

Therefore, P(24 min < X < 33 min) = 0.8997 - 0.50 = <u>0.3997</u>

(c) The probability that a randomly selected athlete uses a stairclimber for​  more than 40 minutes is given by  P(X > 40 minutes)

        P(X > 40 min) = P( \frac{X-\mu}{\sigma} > \frac{40-24}{7} ) = P(Z > 2.28) = 1 - P(Z \leq 2.28)

                                                           = 1 - 0.9887 = <u>0.0113</u>

The above probability is calculated by looking at the value of x = 2.28 in the z table which has an area of 0.9887.

The event of probability that a randomly selected athlete uses a stairclimber for​  more than 40 minutes is unusual because this probability is less than 5% and any even whose probability is less than 5% is said to be unusual.

6 0
3 years ago
What is 2 2/3 dividend by 2/3
Llana [10]
4 is the answer to that
7 0
3 years ago
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A bank manager estimates that an average of two customers enter the tellers' queue every five minutes. Assume that the number of
Dovator [93]

Answer:

The value is  P(X = 3) = 0.1804  

Step-by-step explanation:

From the question we are told that

   The number of customer that enter the tellers every 5 minutes is  \lambda   = 2

Generally the  probability that exactly three customers enter the queue in a randomly selected five-minute period is mathematically represented as

      P(X = 3) = \frac{e^{- \lambda} * \lambda^{3}}{3!}

=>   P(X = 3) = \frac{e^{- 2} * \lambda^{3}}{3!}

=>   P(X = 3) = 0.1804    

4 0
3 years ago
Dema's truck gets 32 mpg on the highway and 18 mpg in the city. The amount of gas he uses A (in gal) is given by A=118c+132h, wh
Zigmanuir [339]

We conclude that he drove 176 miles on the highway

<h3>how many highway miles did he drive?</h3>

Here we have the equation:

A = (1/18)*c + (1/32)*h

Where A is the consumption in gallons of gas, c is the number of miles driven in the city and h is the number of miles driven in the highway.

Here we know that:

A = 8 gallons of gas.

c = 45 miles

Replacing that in the above equation, we can find the value of h.

8 =  (1/18)*45 + (1/32)*h

8 - (1/18)*45 = (1/32)*h

32*(8 - (1/18)*45) = h = 176

We conclude that he drove 176 miles on the highway

if you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

3 0
2 years ago
10 Theo earned £16520 last year and spent 13% of his money on making home improvements.
azamat

Answer:

2147.60

Step-by-step explanation:

7 0
3 years ago
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