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2 years ago

I NEED ANSWER ASAP!!!! AND PLEASE GIVE ANSWER ACCORDING TO THE GRAPH BELOW :)))

Mathematics

1 answer:

podryga [215]2 years ago

5 0

Answer:

ok so put one point on (0, 1) and another on (3, -3)

brainliest pls :)

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What is 108.2x 10 to the 3rd power

xenn [34]

I think it’s 108200....

4 0

3 years ago

• footballs – There are 8 footballs.

inna [77]

Answer:

8 futballs

basketballs 18

beisballs 36

softballs 24

Step-by-step explanation:

dos mas del doble (2) de balones de fut = 8x2 = 16, 16+2 = 18

cuatro menos de 5 veces las pelotas de fut = 8x5 = 40, 40-4 = 36

seis mas de la mitad de beis = 36/2 = 18, 18+6 = 24

LISTO

7 0

2 years ago

Write the equation of the circle below to complete the square. Also determine the area of the circle.

diamong [38]

Answer: $(x-7)^2+(y+2)^2=11^2$ ; $A=121\pi$

Step-by-step explanation:

I have never done a problem like this, so this is my first time attempting it.

The standard form for the equation of a circle is:

$(x-a)^2+(y-b)^2=r^2$

Begin by grouping the 'x' terms and 'y' terms:

$(x^2-14x)+(y^2+4y-68)=0$

Complete the square for the second polynomial:

$(\frac{b}{2} )^2=(\frac{4}{2} )^2=4$

$(x^2-14x)+(y^2+4y+4-4-68)=0$

$(x^2-14x)+(y^2+4y+4)-4-68=0$

$(x^2-14x)+(y^2+4y+4)-72=0$

$(x^2-14x)+(y+2)^2-72=0$

Do the exact same process with the other polynomial:

$(x^2-14x-72)+(y+2)^2=0$

Complete the square:

$(\frac{14}{2} )^2=49$

$(x^2-14x+49-49-72)+(y+2)^2=0$

$(x^2-14x+49)-49-72+(y+2)^2=0$

$(x^2-14x+49)-121+(y+2)^2=0$

$(x-7)^2-121+(y+2)^2=0$

Bring the 121 to the other side to get:

$(x-7)^2+(y+2)^2=121$

$(x-7)^2+(y+2)^2=11^2$

The above expression is the equation of our circle in standard form. It is centered at the coordinates (7, -2) and has a radius of 11 units. The area of a circle if given by:

$A=\pi r^2=121\pi$

8 0

2 years ago

Choose the Δ that seems to be congruent to the given one. [D - top left] [C - top right] [E - center] [A - bottom left] [B - bot

neonofarm [45]

Answer:

Δ BEC ≅ Δ AED

Step-by-step explanation:

Consider triangles BCA and ADB. Each of them share a common side, AB. Respectively each we should be able to tell that AD is congruent to BC, and DB is congruent to CA, so by SSS the triangles should be congruent.

_________

So another possibility is triangles BEC, and AED. As you can see, by the Vertical Angles Theorem m∠BEC = m∠ADE, resulting in the congruency of an angle, rather a side. As mentioned before AD is congruent to BC, and perhaps another side is congruent to another in the same triangle. It should be then, by SSA that the triangles are congruent - but that is not an option. SSA does is one of the exceptions, a rule that is not permitted to make the triangles congruent. Therefore, it is highly unlikely that triangles BEC and AED are congruent, but that is what our solution, comparative to the rest.

Δ BEC ≅ Δ AED .... this is our solution

7 0

3 years ago

Researchers suspect that the average number of units earned per semester by college students is rising. A researcher at Calendul

aleksandrvk [35]

Answer:

All Calendula College students enrolled in the spring.

Step-by-step explanation:

A researcher at Calendula College wishes to estimate the number of units earned by students during the spring semester at Calendula.

To do so, he randomly selects 100 student transcripts from among all Calendula College students enrolled in the spring and records the number of units each student earned in the spring term.

7 0

3 years ago