Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
Answer:
Area of rectangle = l*b
11*9
99
I think it will help you.
Let's try to simplify x^2 + 16. It's a sum of two squares:
x^2 + 16 = 0
x^2 = -16
The problem is, we can't take a square root of a negative. This is where imaginary numbers come in.
Remember that square roots have a plus or minus symbol outside:
±√-16 = ±4i
Our two roots are 4i and -4i. Therefore, the trinomial simplifies to:
(x + 4i)(x - 4i)
If we attempt to divide x + 4 by these two binomials, we will find that 4 and 4i are not like terms. Therefore, we can't simplify this expression.
-3x + 4y = 12
x - y = 1....x = y + 1
-3(y + 1) + 4y = 12
-3y - 3 + 4y = 12
-3y + 4y = 12 + 3
y = 15
x - y = 1
x - 15 = 1
x = 1 + 15
x = 16
one solution (16,15)
x and y i think, I haven't done that in a long time.
