Answer: Lattice parameter, a = (4R)/(√3)
Step-by-step explanation:
The typical arrangement of atoms in a unit cell of BCC is shown in the first attachment.
The second attachment shows how to obtain the value of the diagonal of the base of the unit cell.
If the diagonal of the base of the unit cell = x
(a^2) + (a^2) = (x^2)
x = a(√2)
Then, diagonal across the unit cell (a cube) makes a right angled triangle with one side of the unit cell & the diagonal on the base of the unit cell.
Let the diagonal across the cube be y
Pythagoras theorem,
(a^2) + ((a(√2))^2) = (y^2)
(a^2) + 2(a^2) = (y^2) = 3(a^2)
y = a√3
But the diagonal through the cube = 4R (evident from the image in the first attachment)
y = 4R = a√3
a = (4R)/(√3)
QED!!!
What you have to do is look at all the measurements (ft) and they are labeled. And some of the sides that aren't labeled have clues of what they could be. So when I added, I got 78 ft for my answer.
Answer:
Approximately 11.5 units.
Step-by-step explanation:
We need to find the side opposite to ∠W. We are given the two angles ∠W and ∠X. We are also given that Side X is equal to 7. Therefore, we can use the Law of Sines.
Now, like last time, use the Law of Sines:

We can ignore the first term. Plug in 144 for ∠W, 21 for ∠X, and 7 for <em>x</em>.

Cross multiply:

Answer:
Option B is correct
Step-by-step explanation:
2x² - 6x + 3 = 0
Using Quadratic formula:
x = 
a = 2, b = -6, c = 3
x = 
x = 

x = 2.37

x = 0.63