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Artyom0805 [142]

3 years ago

11

The following data will be used to construct a box plot. What will be the value of the third quartile Q3? 2, 6, 8, 8, 9, 10, 10,

12, 14, 14, 16, 18

1 answer:

tatuchka [14]3 years ago

4 0

Explanation is in the file

tinyurl.com/wtjfavyw

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PLEASE PLEASE PLEASE HELP<br> FAST<br> (The last answer choice is: <br> [-1 4<br> 5 -7 ]

mote1985 [20]

Yes your answer is correct
Just plug in A - 2B + C

5 - 2(4) + 2 = -1
2 - 3(2) + 8 = 4
3 - 2(-1) + 0 = 5
0 - 2(6) + 5 = -5

so
[-1 4]
[5 -7]

6 0

3 years ago

A contaminant is leaking into a lake at a rate of R(t) = 1700e^0.06t gal/h. Enzymes that neutralize the contaminant have been ad

olasank [31]

Answer:

16,460 gallons

Step-by-step explanation:

This is a differential equation problem, we have a constant flow of contaminant into the lake, but also we know that only a fraction of that quantity of contaminant remains because of the enzymes. For that reason, the differential equation of contaminant's flow into the lake would be:

$\frac{dQ}{dt} =1700exp(0.06t)*exp(-0.32t)\\\frac{dQ}{dt} =1700exp(-0.26t)\\$

Then, we have to integrate in order to find the equation for Q(t), as the quantity of contaminant in the lake, in function of time.

$\int\limits^0_t {dQ}=\int\limits^0_t {1700exp(-0.26t)dt}\\Q(t)=\frac{1700}{-0.26} exp(-0.26t)+C \\$

Now, we use the given conditions to replace them in the equation, in order to solve for $C$

$t_{0} =0\\Q_{0}=10,000\\Q_{0}=-6538exp(-0.26*0)+C\\C=10,000+6538=16538$

Then, we reorganize the equation and we replace t for 17 hours, in order to determine the quantity of contaminant at that time:

$Q_{t} =-6538exp(-0.26t)+16538\\Q_{17} =-6538exp(-0.26*17)+16538\\Q_{17} =16460 gallons$

3 0

3 years ago

If Mrs. Ronilo taught 110 students last year and teaches 150 students this year, what is the percent of increase of students in

swat32

36.36 (The Two Decimals repeat)

3 0

4 years ago

Read 2 more answers

Which statements can be used to accurately compare the functions? Select two options. [ g(x) has the lowest minimum. f(x) has th

uysha [10]

The statement all three functions have a y-intercept and the statement f(x) has the greatest maximum can be used to accurately compare the functions.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

From the graph, we can see all the functions have y-intercept:

At x = 0

f(0) = 1

g(0) = -1/2

h(0) = -5

The f(x) has the greatest maximum, which is 10

Thus, the statement all three functions have a y-intercept and the statement f(x) has the greatest maximum can be used to accurately compare the functions.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

4 0

2 years ago

What is the factored expression of 63x^2-3x-6

Murljashka [212]

Answer:

$3(3x-1)(7x +2)$

Step-by-step explanation:

$63x^2-3x-6$

Suppose a generic quadratic equation

$ax^2 + bx + c$

To factor this equation, I need to find its roots. Then we use the quadratic formula of:

$\frac{-b + \sqrt{b^2-4ac}}{2a}$

and

$\frac{-b + \sqrt{b^2-4ac}}{2a}$

So, for the equation 63x ^ 2-3x-6 we have:

$\frac{3 + \sqrt{(-3)^2-4(63)(-6)}}{2(63)} = \frac{1}{3}$

and

$\frac{3 - \sqrt{(-3)^2-4(63)(-6)}}{2(63)} = \frac{-2}{7}$

So:

$(x-\frac{1}{3}) = 0\\\\(3x-1) = 0$

and

$(x - (-\frac{2}{7})) = 0\\\\(x+ \frac{2}{7}) = 0\\\\(7x +2) = 0$

Finally the polynomial is:

$(3x-1)(7x +2)$

6 0

3 years ago