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3 years ago

SOME ONE PLEASE HELP !!!!

Mathematics

1 answer:

Andrei [34K]3 years ago

7 0

x = 20 - -5 = 20 + 5 = 25

y = 16 - 1 = 15

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Ms.Omar runs the school tennis club. She has a bin of tennis balls and rackets. For every 5 tennis balls in the bin, there are 3

stepan [7]

Answer:

see the explanation

Step-by-step explanation:

Let

x ----> number of tennis balls

y ----> number of tennis rackets

we know that

To find out the ratio of tennis balls to tennis rackets, divide the number of tennis ball by the number of tennis rackets

In this problem we have

$\frac{x}{y}=\frac{5}{3}$

$x=\frac{5}{3}y$

That means

The number of tennis balls is three-fifths times the number of tennis rackets

see the attached figure to better understand the problem

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3 years ago

It has rained 3/5 inch in 1/4 hour. If it continues to rain at the same rate,how much rain would fall in an hour

Scorpion4ik [409]

Answer:

2 2/5 inches

Step-by-step explanation:

3/5 x 4

3/5 x 4/1

3/5 x 4/1 = 12/5

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5 0

3 years ago

What is the solution to this equation?<br> x/-4=8

guapka [62]

X=32

Explanation:
When you change sides, if in the left side you are multiplying, when you transfer it to right side you divide. Same thing should be done for addition subtraction.

So /-4 was division and negative number

When we transfered it, it became positive multiplication number

8 0

3 years ago

Find two fractions that are not equivalent to 2/4 but that are equivalent to each other

kvasek [131]

Answer:

1/5 and 2/10

Step-by-step explanation:

4 0

3 years ago

What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?

natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are: $(-2,-1)$ and $(1,0)$ </em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of $\triangle BCD$ are: $B(-3,1), C(3,3)$ and $D(-1,-3)$

Now, the endpoints of the mid-segment of $\triangle BCD$ which is parallel to $BC$ will be the mid-points of sides $BD$ and $CD$ .

<u>Formula for the coordinate of mid-point</u> : $(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})$ , where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two endpoints.

So, the mid-point of $BD$ will be: $(\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)$

and the mid-point of $CD$ will be: $(\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)$

Thus, the endpoint coordinates for the mid-segment of $\triangle BCD$ that is parallel to $BC$ are $(-2,-1)$ and $(1,0)$

4 0

3 years ago

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