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3 years ago

Which two theorems would justify that m∠4 = m∠6, given that m∠5 = m∠6 in the diagram below?

Mathematics

2 answers:

KonstantinChe [14]3 years ago

7 0

Answer:

Step-by-step explanation:

My name is Ann [436]3 years ago

4 0

Answer: D) vertical angles theorem, alternate interior angles theorem

Angle 5 = Angle 6 by the alternate interior angles theorem

Angle 5 = angle 4 by the vertical angles theorem

By the transitive property, we can then say angle 4 = angle 6. These angles are also corresponding angles.

We won't use the angle addition theorem or the right angles theorem.

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The measure of angle J is 120⁰ and is vertical to the measure of angle K. If the measure of angle K is x , what is the value of

Gnoma [55]

Answer:

x=120

Step-by-step explanation:

a vertical angle is equal to each other so if angle J is 120° the so is angle K

4 0

3 years ago

Multiply the polynomials.<br> (4x- + 4x + 6)(7x + 5)

SashulF [63]

$\implies {\blue {\boxed {\boxed {\purple {\sf { \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30}}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$(4 {x}^{2} + 4x + 6)(7x + 5)$

$= \: 7x(4 {x}^{2} + 4x + 6) + 5(4 {x}^{2} + 4x + 6)$

$= \: 28 {x}^{3} + 28 {x}^{2} + 42x + 20 {x}^{2} + 20x + 30$

Combining like terms, we have

$= \: 28 {x}^{3} + (28 {x}^{2} + 20 {x}^{2} ) + (42x + 20x) + 30$

$= \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$

3 0

3 years ago

Please help with the question in the picture!

Umnica [9.8K]

Answer: The answer would be 72/97

Step-by-step explanation: Sin = opposite/hypotenuse. So 72 is opposite angle C and 97 is the hypotenuse (Longest Side).

7 0

3 years ago

The rectangular bar is connected to the support bracket with a 10-mm-diameter pin. The bar width is w = 70 mm and the bar thickn

german

Answer:

P_max = 9.032 KN

Step-by-step explanation:

Given:

- Bar width and each side of bracket w = 70 mm

- Bar thickness and each side of bracket t = 20 mm

- Pin diameter d = 10 mm

- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa

- Average allowable shear stress of pin S = 115 MPa

Find:

The maximum force P that the structure can support.

Solution:

- Bearing Stress in bar:

T = P / A

P = T*A

P = (120) * (0.07*0.02)

P = 168 KN

- Shear stress in pin:

S = P / A

P = S*A

P = (115)*pi*(0.01)^2 / 4

P = 9.032 KN

- Bearing Stress in each bracket:

T = P / 2*A

P = T*A*2

P = 2*(120) * (0.07*0.02)

P = 336 KN

- The maximum force P that this structure can support:

P_max = min (168 , 9.032 , 336)

P_max = 9.032 KN

3 0

3 years ago

Solve for x. Show each step of the solution. 4.5(4 − x ) + 36 = 202 − 2.5(3x + 28)

IgorLugansk [536]

Answer:

Step-by-step explanation:

l,mmmkm

4 0

3 years ago