Answer:
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Step-by-step explanation:
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The numbers that have a digit in the ones place that is 1/10 of the value in the tens place are 1,055 and 3,222.
<h3>What digits are in the ones place?</h3>
The ones place refers to the position immediately before the decimal.
The digit in the tens place is the number immediately left of the ones place.
The numbers that have ones digits that are 1/10 of the digits in the tens place that are 1,055 and 3,222.
That is because 5 is 1/10 of the tens value of 50 and 2 is 1/10 of the 20 in the tens place.
Find out more on the positions of digits at brainly.com/question/579274
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Answer:
<h2>12 and 6</h2>
Step-by-step explanation:
The equation is not properly formatted presumably here is the format.
Given

determine f(2) , and f(−1).
So we are expect to perform substitution operation and return an answers for values of x= 2 and x= -1
1. When x= 2 we have

2. When x= -1 we have

Answer: The mean of this distribution = 61.95
The standard deviation of this sampling distribution (i.e., the standard error= 0.048
Step-by-step explanation:
Given : Data from the U.S. Department of Education indicates that 59% of business graduate students from private universities had student loans.
i.e. proportion of business graduate students from private universities had student loans : p=0.59
sample size : n=105
Then , the mean of the distribution is given by :-

∴The mean of this distribution = 61.95
Then standard deviation of this sampling distribution is given by :-

∴The standard deviation of this sampling distribution (i.e., the standard error= 0.048
<u>Answer- </u>Wendy spent 3 hours on the train
<u>Solution-</u>
The distance between the cities= 500 mi.
She traveled part of the way by bus, and other part by train.
The bus averaged 40 mph, and the train averaged 120 mph.
The entire trip took 6.5 hours.
let d = distance traveled by train
the total distance was given as 500 mi ,
therefore, distance traveled by bus = (500-d) mi
time = distance/speed
⇒ train traveling time + bus traveling time = 6.5 hrs
⇒ 
⇒ d + 3(500-d) = 120(6.5)
⇒ d + 1500 - 3d = 780
⇒ 2d = 720
⇒ d = 360 mi
so d = 360 mi by train
⇒ 360/120 = 3 hrs on the train