
and you can expand the numerator if you wish, it won't be simplified further though.
We have two relations between length and width. One is given in the problem statement. The other is given by the formula for perimeter. We can solve the two equations in two unknowns using substitution.
Let w and l represent the width and length of the sign in feet, respectively.
... l = 2w -12 . . . . . the length is 12 ft less than twice the width
... p = 2(l +w) = 114 . . . . the perimeter is 114 ft
Using the first equation for l, we can substitute for l in the second equation.
... 114 = 2((2w -12) +w)
... 114 = 6w -24 . . . . . . . . simpify
... 138 = 6w . . . . . . . . . . . add 24
... 23 = w . . . . . . . . . . . . . divide by 6
... l = 2w -12 = 2·23 -12 = 34 . . . . use the equation for l to find l
The length and width of the sign are 34 ft and 23 ft, respectively.
Answer:
Where is the question?
Step-by-step explanation:
Where is the question?
Answer:
<OPQ = 23 degrees
Step-by-step explanation:
Given
Interior angles m∠PNO=(x+14) and m∠NOP=(x−1)
Exterior angle = m<OPQ = (5x-2)
The sum of interior angles is equal to the exterior angle, that is;
m∠PNO+m∠NOP = m<OPQ
x+14 + x-1 = 5x-2
2x + 13 = 5x-2
Collect like terms;
2x-5x = -2-13
-3x = -15
x = 15/3
x = 5
Get <OPQ
<OPQ = 5x - 2
<OPQ = 5(5)- 2
<OPQ = 25-2
<OPQ = 23 degrees
Answer:
J
Step-by-step explanation:
x = the number of guests
y = the charges per guest
400 = the rental fee for the banquet
HOPE THIS HELPS <333333
-Silver