The answer is 4:14 (hoped this helped)
Answer:
96
Step-by-step explanation:
To get 5 digit numbers using the digits 0,1,2,3,4 exactly once = 4*4*3*2*1 = 96.
Step 1:
1st digit can be 1, 2,3,4 ( it can't be 0) so there are 4 choices.
Step 2:
2nd digit = 4 choices.
Step 3:
3rd digit = 3 choices
Step 4:
4th digit = 2 choices
Step 5:
5th digit = 1 choice .
So the number of different 5 digit number is 4*4*3*2*1 = 96
Step-by-step explanation:
To find - Enter five expressions: a sum, a difference, a product, a quotient, and one that involves at least two operations that have the value of -3/4 (the fraction)
Solution -
Expression for sum is -
1/4 + (-1) = -3/4
Expression for difference is -
(1/4 - 1) = -3/4
Expression for product is -
(-3/2)(1/2) = -3/4
Expression for quotient is -
(1 - 4)/4 = -3/4
Expression that involves at least two operations is -
-(1/4 + 2/4) = -3/4
Answer:
Step-by-step explanation:
Vertically stretched. The action of vertically stretched is accomplished by altering a in
y = a* abs(x)
What that means is that you make a > 1. In this case, a = 2
So far, what you have is
y = 2*abs(x)
Six units down. The action of 6 units down is accomplished by a number added or subtracted to/from absolute(x). down is minus, up is plus.
y = 2*abs(x) - b. Since we are moving down, b<0
y = 2*abs(x) - 6
Four Units Right. This is the tough one because it is anti intuitive. You would think you should be adding something somewhere to get a right hand movement.
Not true.
To move right you subtract something in the brackets.
y = 2*abs(x - 4) - 6
Graph
Just to make things complete, I have graphed this for you. Desmos is wonderful for this kind of problem.
red: y = abs(x)
blue: y = 2*abs(x - 4) - 6
SOLUTION:
Step 1 :
In this question, we are told that a marketing research company needs to estimate the average total compensation of CEOs in the service industry.
We also have that: Data were randomly collected from 38 CEOs and the 98% confidence interval was calculated to be ($2,181,260, $5,836,180).
Then, we are asked to find the margin error for the confidence interval.
Step 2:
We need to recall that:
![\text{Higher Confidence Interval, CI}_{H\text{ = }}X\text{ + }\frac{Z\sigma}{\sqrt[]{n}}](https://tex.z-dn.net/?f=%5Ctext%7BHigher%20Confidence%20Interval%2C%20CI%7D_%7BH%5Ctext%7B%20%3D%20%7D%7DX%5Ctext%7B%20%2B%20%7D%5Cfrac%7BZ%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D)
![\text{Lower Confidence Interval , CI}_{L\text{ }}=\text{ X - }\frac{Z\sigma}{\sqrt[]{n}}](https://tex.z-dn.net/?f=%5Ctext%7BLower%20Confidence%20Interval%20%2C%20CI%7D_%7BL%5Ctext%7B%20%7D%7D%3D%5Ctext%7B%20X%20-%20%7D%5Cfrac%7BZ%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D)
It means that:

![\text{Margin of error, }\frac{Z\sigma}{\sqrt[]{n}\text{ }}\text{ = }\frac{CI_{H\text{ - }}CI_L}{2}](https://tex.z-dn.net/?f=%5Ctext%7BMargin%20of%20error%2C%20%7D%5Cfrac%7BZ%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%5Ctext%7B%20%7D%7D%5Ctext%7B%20%3D%20%7D%5Cfrac%7BCI_%7BH%5Ctext%7B%20-%20%7D%7DCI_L%7D%7B2%7D)
where,


putting the values into the equation for the margin of error, we have that:
![\text{Margin of error,}\frac{Z\sigma}{\sqrt[]{n}\text{ }}\text{ = }\frac{5,836,180\text{ - }2,181,260\text{ }}{2}](https://tex.z-dn.net/?f=%5Ctext%7BMargin%20of%20error%2C%7D%5Cfrac%7BZ%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%5Ctext%7B%20%7D%7D%5Ctext%7B%20%3D%20%7D%5Cfrac%7B5%2C836%2C180%5Ctext%7B%20%20-%20%7D2%2C181%2C260%5Ctext%7B%20%7D%7D%7B2%7D)

CONCLUSION:
The margin error for the confidence interval is 1, 827, 460