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Naddika [18.5K]
3 years ago
6

How to do questions 19 and 20

Mathematics
1 answer:
Alexeev081 [22]3 years ago
4 0

Answer & Step-by-step explanation:

Using the information given in the question we can form the following 3 equations (in the order of the first 3 sentences)

w = 2h (twice the price)

t = h - 4 ($4 less)

3w + 2h + 5t = 136 (total purchasing and cost)

We can solve all 3 equations for h first, by substituting the first two equations, into the third equations w and t

3(2h) + 2h + 5(h-4) = 136

Simplify

6h + 2h + 5h - 20 = 136

13h = 136 + 20

13h = 156

h = 156/13

h = $12

Using this information, we can solve for w and t

w = 2h

w = 2(12)

w = $24

And finally

t = h - 4

t = 12 - 4

t = $8

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How many solutions are there to each of these equations?
Sloan [31]

Answer:

first one, put value of x= -3 and y = 0

second one, pit vale of x=7 and y= -7

Step-by-step explanation:

first one,

-14(-3) -20(0) =42

or, 42-0 = 42

or, 42 = 42

proved

second one,

-14(7) -20(-7) = 42

or, -98 + 140=42

or, 42 = 42

proved

6 0
2 years ago
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3 years ago
Find the distance of a(1,8) and point c (-8,-6) then find the midpoint of ac
mr Goodwill [35]
\text{MIdpoint =} \bigg(\dfrac{1 + (-8)}{2}, \dfrac{8+(-6)}{2} \bigg) = \bigg(\dfrac{-7}{2}\ , \ \dfrac{2}{2} \bigg) = \bigg(-3.5 \ , \ 1 \bigg)

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I don’t really understand this type of stuff so please help.
ohaa [14]

For 1 and 2, you plot both lines, and wherever they intersect is the solution to the system. Given the equation of a line, I think the easiest way to plot it is to find two points on the line, then draw a line through them. For example, if y=5x-1, then when x=0, you get y=-1; when x=1, you get y=4. So plot the points (0, -1) and (1, 4), then strike a line through.

1. Notice that dividing both sides of 2y=10x-2 by 2 returns y=5x-1, same as the first equation. So the system of equations reduces to one equation, which can have an infinite number of solutions. (This is because for any choice of x or y, you can always find a corresponding value for the other variable.)

2. See attached image. 3x-y=2 is given by the purple line.

For 3-6, you have several options. The two simplest methods of solving them are by substitution or elimination.

3. Like with (1), notice that dividing both sides of the first equation by 2 gives x+3y=9, so there will be an infinite number of solutions.

4. (by substitution) Since y=-7x+3, we can replace y in the second equation:

-7x+3+7x=10\implies3=10

but this is false, so there are no solutions to this system.

5. (by substitution) Since x=2y+2, in the first equation we have

-5(2y+2)+3y=-10y-10+3y=-7y-10=11\implies-7y=21\implies y=-3

Then back in the second equation we find

x=2(-3)+2=-6+2=-4

So (-4, -3) is the only solution here.

6. (by substitution) Notice that the left hand sides of both equations are the same, so we end up with 7 = 12, but this is false, so no solution exists.

5 0
3 years ago
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