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2 years ago

How to do questions 19 and 20

Mathematics

1 answer:

Alexeev081 [22]2 years ago

4 0

Answer & Step-by-step explanation:

Using the information given in the question we can form the following 3 equations (in the order of the first 3 sentences)

w = 2h (twice the price)

t = h - 4 ($4 less)

3w + 2h + 5t = 136 (total purchasing and cost)

We can solve all 3 equations for h first, by substituting the first two equations, into the third equations w and t

3(2h) + 2h + 5(h-4) = 136

Simplify

6h + 2h + 5h - 20 = 136

13h = 136 + 20

13h = 156

h = 156/13

h = $12

Using this information, we can solve for w and t

w = 2h

w = 2(12)

w = $24

And finally

t = h - 4

t = 12 - 4

t = $8

You might be interested in

The overhead reach distances of adult females are normally distributed with a mean of 197.5 cm197.5 cm and a standard deviation

fiasKO [112]

Answer:

a) 5.37% probability that an individual distance is greater than 210.9 cm

b) 75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c) Because the underlying distribution is normal. We only have to verify the sample size if the underlying population is not normal.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 197.5, \sigma = 8.3$

a. Find the probability that an individual distance is greater than 210.9 cm

This is 1 subtracted by the pvalue of Z when X = 210.9. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{210.9 - 197.5}{8.3}$

$Z = 1.61$

$Z = 1.61$ has a pvalue of 0.9463.

1 - 0.9463 = 0.0537

5.37% probability that an individual distance is greater than 210.9 cm.

b. Find the probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

Now $n = 15, s = \frac{8.3}{\sqrt{15}} = 2.14$

This probability is 1 subtracted by the pvalue of Z when X = 196. Then

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{196 - 197.5}{2.14}$

$Z = -0.7$

$Z = -0.7$ has a pvalue of 0.2420.

1 - 0.2420 = 0.7580

75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

The underlying distribution(overhead reach distances of adult females) is normal, which means that the sample size requirement(being at least 30) does not apply.

5 0

3 years ago

Jace invested $65,000 in an account paying an interest rate of 2.5% compounded continuously. Assuming no deposits or withdrawals

Tomtit [17]

Answer:

15 years

Step-by-step explanation:

93400=65000*e^(.025x)

x=14.5 which rounds to 15

7 0

3 years ago

PLEASE HELP

katrin2010 [14]

The game that is used for the scenario above in terms of fair play is using a balloon. Here, the player will hit the balloon.

<h3>What is the scenario under the balloon game?</h3>

The rule of play are:

This is a classic game with simple rules which are:

Each player to hit the balloon up and it bonce into the air but when one should not allow it to touch the ground.,
Players would be tied together in twos and they will juggle a lot of balloon and it have to be more than 1 balloon with one of their hands tied to their back.

A scenario of the worksheet game whose expected value is 0 is given below:

Assume that it costs about $1 for a player to play the billon game and as such, if the player hits a balloon, they will be given $3. what can you say. Can you say that it this game is fair or not? and who has the biggest advantage.

Solution

Note that a game is ”fair” if the expected value is said to be 0. When a player is said to hits a balloon, their net profit often increase by $4. So when the player do not hit a balloon, it drops to $1.

(4)(0.313) + (-1)(0.313)

= 0.939 approximately

Thus, the expected value is $0.939 which tells that the game is fair.

Learn more about fair play from

brainly.com/question/24855677

#SPJ1

4 0

2 years ago

1) A scuba diver dives beneath the surface of the water 34 feet. He swims up 13 feet closer to the surface, then swims back down

Nataliya [291]

1. 0 - 34 + 13 - 5 = -26.....26 ft below the surface

2. y = 15x + 50
220 = 15x + 50
220 - 50 = 15x
170 = 15x
170/15 = x
11 1/3 = x......he worked 11 1/3 hrs.......not sure about this...because it does not specify how many visits he made...but if this was just for 1 visit, then he worked 11 1/3 hrs

8 0

3 years ago

At 2 hours before sunset, the temperature is 0°F. At 2 hours after sunset, the temperature is −4°F. Identify the slope, y-interc

Liula [17]

Answer

slope: 1

y-intercept: 0,–2

x-intercept: -2,0

Step-by-step explanation

I just did this question

7 0

3 years ago