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Angelina_Jolie [31]
2 years ago
11

Today, there were 3 students absent from the math class. Each students that attended school solved 17 equations in math class. A

t the end of the class the teacher told the students that together they solved 408 equations today. How many students are this class if no one is absent?
Mathematics
1 answer:
nika2105 [10]2 years ago
7 0

Answer:

  • 27 students

Step-by-step explanation:

<u>Number of students present in the math class:</u>

  • 408/17 = 24

<u>Number of students in this class:</u>

  • 24 + 3 = 27
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Answer:

x<13

Step-by-step explanation:

To solve this, we want to have the isolate the variable x on the left side, by itself without a coefficient. All we have to do to do this is add 4 to both sides, cancelling out the -4 and getting x<13

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How many flowers, spaced every 6 inches, are needed to surround a circular garden with a 10 foot radius?
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To solve this problem you must apply the proccedure shown below:

1. You must calculate the perimeter of the circle:

The radius of the circle in inches is:

radius=\frac{(10ft)(12in)}{1ft}=120in

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Which property justifies the following equation? <br> 7(6+0+5)= 7(6+5)
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A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

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P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

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