Complete Question
A recent study found that hourly wages earned by employees possessing a master's degree are distributed normally with a mean of $27.50 and standard deviation of $3.50
At a recent job fair, Intel boasted that they paid master's graduates more than 90% of all
employers. If we interpret their claim as a percentile, what hourly wage must they offer
employees with master's degrees?
Answer:
The value is 
Step-by-step explanation:
From the question we are told that they paid master's graduates more than 90% of all
Generally from the z-table the z-score for 90% is 
This z-score can be mathematically represented as

Here x is the hourly wage they offer employees with master's degrees
substituting $27.50 for
and $3.50 for
we have

=> 
7x + 18 = 8x
8x-7x = 18
x = 18
3y = 2x
3y = 2(18)
3y = 36
y = 12
Simple interest formula: I=prt
t=6yrs
p=1250
r=2.7%
I=prt
I=(1250)(.027)(6)
I=202.50
Simple interest paid will be $202.50
The function is <span>b(x)= |x+4|,
which means that b(-10)=|-10+4|, since we can replace both x-es above with any number. (This is what the rule means.)
Further, |-10+4|=|-6|. We know that the absolute value gives us always positive values, so |-6|=6.
Thus, the answer is 6.
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I would say the answer is K and M