We have
(a + b)² = a² + 2ab + b²
so that with a = x² and b = 5, we have
x⁴ + 10x² + 25 = (x² + 5)²
Next, we have
a² - b² = (a - b) (a + b)
so that with a = x and b = √5 i,
x² + 5 = x² - (-5) = (x - √5 i) (x + √5 i)
So, the complete factorization over the complexes is
(x - √5 i)² (x + √5 i)²
Answer:
Solution given:
South distance :base[b]=80milea
East distance :perpendicular [p]=35miles
Now
<S=?
we have
=24°
24° bearing should be taken from south airport to East airport.
Hello :
the center of this cercle is : O( 0, 0)
calculate the slope m of the line : OA .. A (3,-4)
m= (yA - yO) / (xA- xO)
m = (-4-0)/(3-0)
m= -4/3
if : k the slope of the tangent : k×m = -1 (the tangent perpendiclar of : OA)
k× (-4/3) = -1
k = 3/4
an equation of this tangent is : y - (-4) = (3/4)(x-3)
Answer:
True
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k) = (- 4, - 9), thus
y = a(x + 4)² - 9
To find a substitute the coordinates of the zero (- 7, 0) into the equation.
0 = a(- 7 + 4)² - 9, that is
0 = 9a - 9 ( add 9 to both sides )
9a = 9 ( divide both sides by 9 )
a = 1, thus
y = (x + 4)² - 9 ← expand factor using FOIL
y = x² + 8x + 16 - 9
y = x² + 8x + 7
