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3 years ago

Does Y= -2/3x + 3 & Y=2/3x + 2 have unlimited solutions?

Mathematics

1 answer:

notsponge [240]3 years ago

6 0

Answer:

x = 3/4

y = 2.5

Step-by-step explanation:

No there is just one.

Equate the ys

-2/3 x + 3 = 2/3 x + 2 Add 2/3 x to both sides

3 = 2/3 x + 2/3x + 2 Combine

3 = 4/3 x + 2 Subtract 2

3-2 = 4/3 x Multiply by 3

1 * 3 = 4x Divide by 4

3/4 = x

====================

y = 2/3 x + 2

y = 2/3 * 3/4 + 2

y = 6/12 + 2

y = 1/2 + 2

y = 2 1/2

y = 2.5

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Step-by-step explanation:

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3 years ago

Whats the diffrence of 2 2/3 - 1 2/5 write answer in simplest form

Fofino [41]

$2 \frac{2}{3}-1 \frac{2}{5}=2 \frac{2 \times 5}{3 \times 5}-1 \frac{2 \times 3}{5 \times 3}=2 \frac{10}{15}-1 \frac{6}{15}=\boxed{1\frac{4}{15}}$

3 0

3 years ago

Read 2 more answers

Choose the correct answer 1 1/12 - 7/10 greater than half or less than half

CaHeK987 [17]

Answer:

less than half

Step-by-step explanation:

13/12 - 7/10 = 23/60

5 0

3 years ago

Help me pleazzzzzzzzeeeeeee

uranmaximum [27]

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6 0

3 years ago

Approximate the change in the volume of a sphere when its radius changes from r= 5ft to r= 5.1ft (v(r)= 3/4 pi r^3)?

leva [86]

Answer:

18.03 cubic feet

Step-by-step explanation:

Hello,

Step 1

find the volume of the sphere when radius= 5 ft

$v(r)= \frac{3}{4} \pi r^3\\v(5)= \frac{3}{4}\pi (5\ ft)^3\\v(5)= \frac{3}{4}\pi *125\ ft^{3} \\v(5)=294.52\ cubic\ feet\\$

Step 2

find the volume of the sphere when radius= 5.1 ft

$v(r)= \frac{3}{4}\pi r^3\\v(5.1)= \frac{3}{4} \pi (5.1\ ft)^3\\v(5.1)= \frac{3}{4}\pi *132.651\ ft^{3} \\v(5.1)=312.551\ cubic\ feet\\\\$

Step 3

Compare the Volumes to find the change

$\frac{v(r_{2})}{v(r_{1})} =\frac{312.551}{294.52} =1.06$

the volumen of the sphere with radius = 5.1 is 1.06 times bigger than the first one(r=5)

Now, find the change

$change= {v(r_{2})-{v(r_{1})}} \\change=312.551\ cubic\ feet\ -294.52 cubic feet \\ change=18.031\ cubic\ feet$

change=18.03 cubic feet

Have a great day.

4 0

3 years ago