All categories

3 years ago

Please help me anyone ;(

Mathematics

1 answer:

Sergio039 [100]3 years ago

5 0

Answer:

9 tables

Step-by-step explanation:

All we have to do is see how many time 6³/₄ ft. can fit in 60³/₄ ft. through division.

60 ³/₄ ÷ 6 ³/₄ =

²⁴³/₄ ÷ ²⁷/₄ =

²⁴³/₄ × ⁴/₂₇ =

²⁴³/₂₇ =

9 tables

You might be interested in

-6p - 20 = -2p +4(1 - 3p)

kirza4 [7]

Answer:

p = 3

Hope this helps

7 0

3 years ago

Read 2 more answers

Solve for x.<br> 2(x - 4) = 6(x+2)

nekit [7.7K]

The answer is x= -5 !!!!

6 0

3 years ago

Read 2 more answers

Jordan has 3.2 liters of paint left. how can she convert this number to millileters?

Olenka [21]

See attached photo.

~

8 0

3 years ago

Jaina and Tomas compare their compound interest accounts to see how much they will have in the accounts after three years. They

stellarik [79]

Formula for compound interest is

Interest = Amount - Principal

Interest = $P(1+r)^{t}$ - P

Where r = rate in percent

t = time in years

For Jaina,

P = $300

r= 7%

t = 3 yrs

So, Interest = $300(1+0.07)^{3}$ - 300

For Tomas

P = $400

r= 4%

t = 3 yrs

So, Interest = $400(1+0.04)^{3}$ - 400

So pair of equations for Jaina and Tomas are

Interest = $300(1+0.07)^{3}$ - 300

Interest = $400(1+0.04)^{3}$ - 400

5 0

3 years ago

Read 2 more answers

Find the work done by force dield f(x,y)=x^2i+ye^xj on a particle that moves along parabola x=y^2+1 from(1,0) to (2,1)

NemiM [27]

Call the parabola $P$ , parameterized by $\mathbf r(y)=\langle y^2+1,y\rangle$ with $0\le y\le 1\rangle$ . Then the work done by $\mathbf f(x,y)$ along $P$ is

$\displaystyle\int_P\mathbf f(x,y)\cdot\mathrm d\mathbf r=\int_{y=0}^{y=1}\mathbf f(x(y),y)\cdot\dfrac{\mathrm d\mathbf r(y)}{\mathrm dy}\,\mathrm dy$
$=\displaystyle\int_0^1\langle(y^2+1)^2,ye^{y^2+1}\rangle\cdot\langle2y,1\rangle\,\mathrm dy$
$=\displaystyle\int_0^1(2y^5+4y^3+2y+ye^{y^2+1})\,\mathrm dy=\frac73-\frac e2+\frac{e^2}2$

8 0

3 years ago