
You pass the free terms wich don't contain 'x' in the othe part of the equal with changed signe ans the same for the terms wich contain x.
Answer:
13 1/3 and 6 2/3.
Step-by-step explanation:
Let the 2 parts be x and (20 - x).
So x^2(20 - x) must be a maximum.
y = x^2(20 - x)
y = 20x^2 - x^3
Finding the derivative):
y' = 40x - 3x^2 = 0 for maxm/minm value.
x( 40 - 3x) = 0
40 - 3x = 0
3x = 40
x = 40/3.
This is a maximum because the second derivative y" = 40 - 6x = 40 - 6(40/3)) is negative.
So the 2 numbers are 13 1/3 and 6 2/3.
Answer:
C.5.7
Step-by-step explanation:
plug in the x value then add 4.5 to 1.2 and booyyah
Answer:
C
Step-by-step explanation: