Please help me with this math problem!! :) Will give BRAINLIEST!! :)

Mathematics

1 answer:

Kitty [74]1 year ago

7 0

The rate of change will be positive and a point in the graph will be (1,250);
the function then would be y = 250x;
after 1 year she will owe USD 5,250;
she will have to make 33 payments.

How to form equation using slope and one point?
y - y1 = m(x - x1) is the equation of a straight line's point slope form, where m is the line's slope and (x1, y1) is the point through which the provided line passes.

Using slope-point equation, the equation for the payment can be taken as:
y-250 = [(500-250)/(2-1)]*(x-1)
y - 250 = 250*(x-1)
y = 250 + 250x - 250 = 250x;
Putting x = 12, for a year the amount paid is USD 3,000.
Amount she owes = USD (8250-3000) = USD 5,250;
Total amount to be paid (in USD) = 8250
Amount paid per month (in USD) = 250
Thus, number of payments required = 8250/250 = 33

Thus, the rate of change will be positive and a point in the graph will be (1,250); the function then would be y = 250x; after 1 year she will owe USD 5,250; she will have to make 33 payments.

To learn more about slope point equation form tap on the link below:
brainly.com/question/24907633

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If f(x)=x-6 and g(x)=x1/2(x+3), find g(x) times f(x)

Elden [556K]

To solve this problem you must apply the proccedure shown below:
1. You have the following functions given in the problem above:
$f(x)=x-6 
$ and $g(x)=x1/2(x+3)=x(x+3)/2$ 
2. You have that g(x) times f(x) can be written as g(x)*f(x). Therefore, you must multiply f(x) * g(x), as following:
 $g(x)*f(x)=(x-6)*x(x+3)/2$ 
3. Applying the distributive property, you have:
 $g(x)*f(x)=( x^{3} + 3x^2 - 6x^{2} -18x)/2$
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The answer is: $g(x)*f(x)=(x^{3} - 3x^{2} -18x)/2$