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Anestetic [448]
3 years ago
14

PLEASE HELP ME WRITE A EQUATION FOR THIS! I WOULD REALLY APPRECIATE IT!

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
5 0

Answer:

y= -x-1

Step-by-step explanation:

weeeeeb [17]3 years ago
5 0
Y=x-1 because the y intercept is -1 and the x would be rise over run which is 1
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Santa has 75 toys left in his sleigh. If the house has 5 kids, how many toys can he<br> leave?
jolli1 [7]

Answer:

Santa can leave 15 toys at their house.

Step-by-step explanation:

5 0
3 years ago
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Question 12. How much more will her shirt cost in Union City than in River 10 points
alexandr402 [8]

Step-by-step explanation:

we need the whole question

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3 years ago
From three chocolate bars we can make at most five chocolate rabbits and
Luden [163]

Answer: About 49.

Explanation:

16 × 3 = 48.

With some left over, you can infer they can make atleast 1 more bar.

48 + 1 = About 49 chocolate bars.

4 0
3 years ago
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th
Verizon [17]

Answer:

(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422

(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778

And we are 95% confident that the true difference means are between 1.422 \leq \mu_1 -\mu_2 \leq 2.778

Step-by-step explanation:

We know the following info:

\bar X_1 = 21.9 sample mean for group 1

\bar X_2 = 19.8 sample mean for group 2

s_1 = 3.4 sample standard deviation for group 1

s_2 = 3.5 sample standard deviation for group 2

n_1 = 200 sample size group 1

n_2 = 200 sample size group 2

We want to find a confidence interval for the difference of means and the correct formula to do this is:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

Now we just need to find the critical value. The confidence level is 0.95 then the significance is 1-0.95 =0.05 and \alpha/2 =0.025. The degrees of freedom are given by:

df= n_1 +n_2 -2= 200+200-2= 398

The critical value for this case would be :t_{\alpha/2}=1.966  

And replacing into the confidence interval formula we got:

(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422

(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778

And we are 95% confident that the true difference means are between 1.422 \leq \mu_1 -\mu_2 \leq 2.778

5 0
3 years ago
What is the period of the function f(x)=sin(x/3) ?
vitfil [10]
<h3>Answer: 6pi radians</h3>

(this is equivalent to 1080 degrees)

======================================

Explanation:

f(x) = sin(x/3)

is the same as

f(x) = 1*sin( (1/3)(x-0) )+0

and that is in the form

f(x) = A*sin( B(x-C) )+D

The letters A,B,C,D are explained below

A = helps find the amplitude

B = 2pi/T, where T is the period

C = determines phase shift (aka left/right shifting)

D = determines vertical shift = midline

All we care about is the value of B as that is the only thing that is connected to the period T

--------

Compare f(x) = 1*sin( (1/3)(x-0) )+0 with f(x) = A*sin( B(x-C) )+D and we see that B = 1/3, so,

B = 2pi/T

1/3 = 2pi/T

1*T = 3*2pi ... cross multiply

T = 6pi

The period is 6pi radians. This is equivalent to 1080 degrees. To convert from radians to degrees, you multiply by (180/pi).

6 0
3 years ago
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