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Anestetic [448]
3 years ago
14

PLEASE HELP ME WRITE A EQUATION FOR THIS! I WOULD REALLY APPRECIATE IT!

Mathematics
2 answers:
Scorpion4ik [409]3 years ago
5 0

Answer:

y= -x-1

Step-by-step explanation:

weeeeeb [17]3 years ago
5 0
Y=x-1 because the y intercept is -1 and the x would be rise over run which is 1
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Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
aliina [53]

Answer:

16

Step-by-step explanation:

Solve 5 to the power of x minus 3 to the power of x when x=2.

So, you do 5 to the power of 2 minus 3 to the power of 2, which is 25-9=16

8 0
3 years ago
Read 2 more answers
- x² - 4x + 12 = 0 <br>how do u solve by completing the square​
MrRa [10]

Answer:

0

Step-by-step explanation:

Simplifying

x2 + -4x + -12 = 0

Reorder the terms:

-12 + -4x + x2 = 0

Solving

-12 + -4x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.

(-2 + -1x)(6 + -1x) = 0

8 0
3 years ago
Select True or False for each statement.
SSSSS [86.1K]

\left( \dfrac 1 {64} \right)^{- 5/6} =64^{5/6} = (\sqrt[6]{64})^5 = 2^5 =32

TRUE

\sqrt[5]{36^4}=36^{4/5}

which surely isn't 36.  FALSE

\sqrt{12} - \dfrac 2 5 \sqrt{75} = 2 \sqrt{3} -\dfrac 2 5 (5) \sqrt{3} = 0

FALSE

For the fourth one we have a

\sqrt{98b} + \sqrt{2b}

which isnt

10\sqrt{b}

so this is FALSE.

\dfrac{1}{(\sqrt 5 - \sqrt 6)^2}

= \dfrac{1}{(\sqrt 5 - \sqrt 6)^2} \cdot \dfrac{(\sqrt 5 + \sqrt 6)^2}{(\sqrt 5 + \sqrt 6)^2}

= \dfrac{(\sqrt 5 + \sqrt 6)^2}{ ( (\sqrt 5 - \sqrt 6)(\sqrt 5 + \sqrt 6))^2}

= \dfrac{(\sqrt 5 + \sqrt 6)^2}{( 5-6)^2}

=(\sqrt 5 + \sqrt 6)^2

No fractions in that one so FALSE.

3 0
3 years ago
Which of the following expressions represents the phrase "19 less than a number"?
kipiarov [429]
A, because n is having 19 taken from it
5 0
4 years ago
Read 2 more answers
The difference of twice a number g and 10 is 24
ANTONII [103]
The number g is 7
24-10 = 14
14/2=6
8 0
3 years ago
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