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liraira [26]
3 years ago
11

-4x <8 solve the inequality

Mathematics
1 answer:
katovenus [111]3 years ago
6 0

Answer:

x>−2

Step-by-step explanation:

−4x<8

Step 1: Divide both sides by -4.

−4x

−4

<

8

−4

x>−2

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Pls help me its timed and for a grade I really struggle with this.
nexus9112 [7]

Answer:

scalene

Step-by-step explanation:

you can tell by the shape

5 0
3 years ago
I just need no. a please help me to prove this. ​
OleMash [197]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    and         cos A = cos B · cos C

scratchwork:

  A + B + C = π

               A = π - (B + C)

         cos A = cos [π - (B + C)]                              Apply cos

                    = - cos (B + C)                                    Simplify

                    = -(cos B · cos C - sin B · sin C)          Sum Identity

                    = sin B · sin C - cos B · cos C               Simplify

cos B · cos C = sin B · sin C - cos B · cos C               Substitution

2cos B · cos C = sin B · sin C                                        Addition

                     2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}                                     Division

                     2 = tan B · tan C

\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}

<u>Proof LHS → RHS</u>

Given:                              A + B + C = π

Subtraction:                     A = π - (B + C)

Apply tan:                  tan A = tan(π - (B + C))

Simplify:                               = - tan (B + C)

\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)

Substitution:                        = -(tan B + tan C)/(1 - 2)

Simplify:                               = -(tan B + tan C)/-1

                                            = tan B + tan C

LHS = RHS:   tan B + tan C = tan B + tan C  \checkmark

5 0
2 years ago
What is the sum of StartRoot negative 2 EndRoot and StartRoot negative 18 EndRoot?
Darya [45]

Answer:

4 \sqrt{2} i

Step-by-step explanation:

We want to find the sum of

\sqrt{ - 2}  +  \sqrt{ - 18}

We can rewrite this as

\sqrt{ 2 \times  - 1}  +  \sqrt{ 18 \times  - 1}

This becomes;

\sqrt{2}  \times  \sqrt{ - 1}  +  \sqrt{18}  \times  \sqrt{ - 1}

Recall that;

i =  \sqrt{ - 1}

This implies that;

\sqrt{2} i + 3 \sqrt{2} i

Combine like terms:

4 \sqrt{2} i

3 0
3 years ago
There is an attachment for my question relating to geometry...thank you for the help
Tomtit [17]
Hello I hope this helps. I'm pretty sure this is the answer.
 
Part A: C
Part B: A


6 0
3 years ago
Read 2 more answers
PLZ HELP I NEED TO TURN THIS IN TODAY
Cerrena [4.2K]

Answer:

The top one

Step-by-step explanation:

Just count how many are in each catagory

5 0
3 years ago
Read 2 more answers
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